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Mathematics 12 Online
zarkam21:

??

zarkam21:

1 attachment
Vocaloid:

both of these can be solved by applying KE = (1/2)mv^2 and solving for the appropriate value

zarkam21:

okay so for the first one it would KE=(1/2)(34)*8.5^2

zarkam21:

right?

Vocaloid:

good

zarkam21:

ke=1228.25

Vocaloid:

good, just don't forget units (joules)

zarkam21:

okay and for the second one KE=1/2*1150*27000^2

Vocaloid:

keep in mind that 27000 is the kinetic energy not the velocity

zarkam21:

ohhh so what would i substitute for the v then

Vocaloid:

the question is asking you to solve for v so this is your unknown

zarkam21:

so KE=1/2*1150*v^2

Vocaloid:

yup, solve that for v

zarkam21:

575?

Vocaloid:

check your calculations again

zarkam21:

okay

zarkam21:

30

zarkam21:

because i squared both sides. then i multiplied 1150*1/2 all under a sqrt

Vocaloid:

27,000 = (1/2)(1150)v^2 keep in mind the symbol only applies to the v to isolate v^2 you must divide both sides by (1/2) and 1150 first and ~then~ take the square root

zarkam21:

27

Vocaloid:

27,000/(1/2)/(1150) = ?

zarkam21:

1 attachment
Vocaloid:

27,000 divided by (1/2) and then divided again by 1150 equals...?

zarkam21:

49

zarkam21:

47

zarkam21:

because it is 46.9

Vocaloid:

good, that's your v^2 value, now find v

zarkam21:

just sq it right?

Vocaloid:

other way around it's already squared so you want to take the square root

zarkam21:

6.9

Vocaloid:

good, 6.9 m/s. kind of a slow truck but the numbers work out.

zarkam21:

cool thanks

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