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Mathematics 12 Online
Comerpickles:

http://prntscr.com/i1thga

Comerpickles:

@Vocaloid

Vocaloid:

just split the shape into a rectangle + a triangle|dw:1516213782841:dw|

Vocaloid:

|dw:1516213790254:dw| then find the area of the triangle + rectangle and add them together

Comerpickles:

How would I know where the area is? By counting the squares?

Vocaloid:

area of triangle = (1/2)(base)(height) area of rectangle = (width)(length)

Comerpickles:

Sort of like this? http://prntscr.com/i1tjxe

Vocaloid:

good, keep going

Comerpickles:

http://prntscr.com/i1tkxu

Vocaloid:

the height is 6 not 5, base is 3, so calculate the area of the triangle

Comerpickles:

6*3?

Vocaloid:

area for a triangle is (1/2)(base)(height)

Comerpickles:

18

Vocaloid:

don't forget the 1/2

Comerpickles:

What do I do with that again?

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid area for a triangle is (1/2)(base)(height) \(\color{#0cbb34}{\text{End of Quote}}\)

Comerpickles:

9

Comerpickles:

?

Vocaloid:

good, the area of the triangle is 9 now find the area of the rectangle and add them together

Comerpickles:

24

Vocaloid:

re-count the base and height of the rectangle

Comerpickles:

6 and 5

Comerpickles:

(1/2) 6*5 = 15

Vocaloid:

the area of a rectangle is just (base)(height)

Comerpickles:

Oh

Comerpickles:

39

Vocaloid:

good, so 39 = your ans

Comerpickles:

I tried to meet the problem halfway on this one http://prntscr.com/i1tsdq

Vocaloid:

|dw:1516214987042:dw|

Vocaloid:

|dw:1516214993696:dw|

Vocaloid:

|dw:1516215007977:dw|

Vocaloid:

try to apply the same formulas from before area of triangle = (1/2)(base)(height) area of rectangle = (base)(height)

Comerpickles:

"9" http://prntscr.com/i1ttyr

Comerpickles:

(1/2) 6 x 3 = 9

Vocaloid:

area of a rectangle is just base * height

Comerpickles:

18 then

Vocaloid:

good, keep going

Comerpickles:

I forgot what to do next, because it says to find the area of the Polygon

Vocaloid:

find the area of the other triangles

Comerpickles:

http://prntscr.com/i1ty24

Vocaloid:

the triangle on the right hand side is 4, 3 not 4,5

Comerpickles:

Ohhh

Vocaloid:

anyway, using these values, calculate the area of all the other triangles remember that triangle = (1/2)(base)(height)

Comerpickles:

6, 1.5, and 9

Comerpickles:

All of it added with 9 = 25.5

Vocaloid:

the area of the rectangle is 18 not 9, so the final answer is 34.5

Comerpickles:

Ohhh, forgot, I was looking at the area I added for the width and height

Comerpickles:

I gave a little head start http://prntscr.com/i1u1uz

Vocaloid:

the area of the rectangle is 28 and the circular parts are closer to 8 (just estimating) so I would go with answer choice 2

Comerpickles:

http://prntscr.com/i1u399

Comerpickles:

This I shouldn't mess up since they mention the shapes

Vocaloid:

area of a parallogram is also base*height for the rectangle you will have to use the pythagorean theorem to find the length of that slanted slide

Comerpickles:

You mean like this? http://prntscr.com/i1u4rq

Vocaloid:

|dw:1516216363603:dw|

Vocaloid:

|dw:1516216368705:dw|

Vocaloid:

find the two marked slanted slides

Comerpickles:

3?

Comerpickles:

3,8?

Vocaloid:

|dw:1516216509795:dw|

Vocaloid:

use the pythagorean theorem to find the hypotenuse leave your answer in radical form

Comerpickles:

For that triangle 2,8?

Vocaloid:

the hypotenuse is a number not a coordinate point

Vocaloid:

remember a^2 + b^2 = c^2 for a triangle hypotenuse

Comerpickles:

Sorry, I'm a bit rusty when it comes to this stuff

Vocaloid:

for a right triangle, a and b are the legs and c is the hypotenuse

Vocaloid:

|dw:1516216705869:dw|

Vocaloid:

a^2 + b^2 = c^2, find c (leave in radical form)

Comerpickles:

C=2 with the square root of 10

Vocaloid:

good, now repeat the same process with the smaller triangle

Vocaloid:

|dw:1516216861359:dw|

Comerpickles:

3,1-Ah you beat me to it

Vocaloid:

good, now find the hypotenuse

Comerpickles:

Square root \[\sqrt{10}\]

Vocaloid:

good, so the area of the rectangle is sqrt(10) * 2 * sqrt(10) = 2*10 = 20 now add the area of the parallelogram to this

Comerpickles:

\[\sqrt{10*2} =2*10=20\] Like this?

Vocaloid:

it's sqrt(10) * sqrt(10) * 2 the 2 needs to be outside the radical and there needs to be another square root 10 to cancel out the radicals

Comerpickles:

\[\sqrt{10} * \sqrt{10} *2\]

Comerpickles:

Like that?

Vocaloid:

yes

Vocaloid:

now add that to the area of the parallelogram

Comerpickles:

That times 24?

Vocaloid:

|dw:1516217524656:dw|

Vocaloid:

the base is 6 and the height is 1 for the parallelogram so 6*1 + 20 = 26 = your answer

Comerpickles:

Just bxh or 1/2bxh?

Vocaloid:

for a parallelogram it is base * height

Comerpickles:

AHa

Comerpickles:

http://prntscr.com/i1uhb3

Comerpickles:

Last one

Vocaloid:

|dw:1516217662023:dw|

Vocaloid:

|dw:1516217666746:dw|

Vocaloid:

the base and height of the triangle are 6 and 3 the base and height of the rectangle are 7 and 6 calculate the total area

Comerpickles:

18+21=39

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid area of triangle = (1/2)(base)(height) area of rectangle = (width)(length) \(\color{#0cbb34}{\text{End of Quote}}\)

Comerpickles:

So I guess 39 is my answer

Vocaloid:

check your math again, you mixed up the formulas

Comerpickles:

42+9, excuse me. Didn't know how I didn't see 6 and 3 were a triangle. 51

Vocaloid:

good, 51 = your answer

Comerpickles:

Thanks

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