Question

Can someone please explain to me how to do these problems?

Answer 1

@Vocaloid @563blackghost @Shadow

Answer 2

SUMMONED!

Answer 3

hi :3 i can help :D

Answer 4

Lol! I dont understand what i did wrong, and thanks!

Answer 5

So let's do the first pic first.

We would need to use distance formula for the distance between A and B.

\(\large\bf{d=\sqrt{(2-4)^{2} + (1-5)^{2}}}\)

Simplify this.

Answer 6

Ummm... i forgot. Sorry

Answer 7

We follow by PEMDAS to solve.

First we do the paranethesis...

\(\large\bf{d=\sqrt{(-2)^{2} + (-4)^{2}}}\)

Now we apply the exponent.

\(\large\bf{d=\sqrt{(4+16)}}\)

What is the distance?

Answer 8

oh okay. 20. Now do i square that?

Answer 9

it would be the \(\large\bf{\sqrt{20}}\)...not just 20...that would be wrong.

You cannot square this number perfectly so we keep it as it is...

Answer 10

so it is B.

Answer 11

OMG that was much easier than it looks.

Answer 12

^-^ try not to think to hard about it, cause most of the time if you do you get it wrong....

Answer 13

So now on to 2?

Answer 14

Yes. the only other answer i think it would be is B, but not sure.

Answer 15

let meh see first ;)

Answer 16

Okay, thx

Answer 17

so sorry i was afk for a bit...

Answer 18

your fine

Answer 19

wait..

Answer 20

okay

Answer 21

im kind of confused on this one honestly...@Vocaloid can you look at this a bit...

Answer 22

@Vocaloid

Answer 23

Yeah i was pretty confused too

Answer 24

A is the answer e.e

Answer 25

I got it wrong though):

Answer 26

OH I SEE

Answer 27

Okay the rule of a counterclockwise rotation of 270 degrees is...

\(\large\bf{(x,y) \rightarrow (y,-x)}\)

So the transformation of point L is \(large\bf{(2,-2) \rightarrow (-2,-2)}\)

We then follow by a 1 unit translation to get `(-2,-3)` so it is B. Just like you said :3

Answer 28

whoops latex mistake :P

Answer 29

Oh okay, i see now.

Answer 30

that one was tricky >.<

Answer 31

Next one?

Answer 32

Yeah, that confused me.

Answer 33

I know the formulas. I am just keep getting something thats not the answer

Answer 34

Okay so we need to first identify the volumes of both shapes..

\(\Large\bf{Volume~of~a~cone:V= \frac{1}{3} \pi r^{2} h}\)

\(\Large\bf{Volume~Of~a~cylinder: V = \pi r^{2} h}\)

So we plug in our information.

`remember to find the radius we divide the diameter by 2`

\(\Large\bf{Cone: V=\frac{1}{3} (3.14) (1)^{2} 3}\)

\(\Large\bf{Cylinder" V=(3.14)1^{2}(7)}\)

Can you simplify these?

Answer 35

Yes. The cone i got 3.17, and the Cylinder I got 21.98

Answer 36

Cone was close! It is actually 3.14. The Cylinder volume is correct.

Now we must subtract these two to find the difference.

\(\large\bf{21.98-3.14=?}\)

Answer 37

Wait, what did i do wrong for the cone? and 18.84

Answer 38

Oh, i got 9.51. I have no idea how i got that though. (:

Answer 39

The equation goes by \(\large\bf{V=\frac{1}{3}(3.14)(1^{2})3}\)

The \(\large\bf{1^{2}=1}\) and \(\large\bf{\frac{1}{3} \times 3 = 1}\)

so we multiply this....

\(\large\bf{V=3.14 \times 1 \times 1 = 3.14}\)

Yes 18.84 is correct, so it is A. :D

Answer 40

18.84 is the answer. Thank you!

Answer 41

Your welcome ^_^