Question

Would this be the same?
A Squirrel jumps into the air with a velocity of 4 m/s at an angle of 50 degrees. What is the maximum height reached by the squirrel?
A: 0.34m
B: 0.48m
C: 1.2m
D: 0.26m

Answer 1

0 = 4sin(50) + (-9.8)t

Answer 2

that's one way to do it but there's a faster way using the last kinematics equation

vf^2 = vi^2 + 2a * delta y

where vf = 0, vi = initial velocity = 4sin(5), a = -g, and delta y is the height, solve for height

Answer 3

*** should be 4sin(50)

Answer 4

0 = 4sin(50)^2 + 2(-9.8) * h

Answer 5

0.12

Answer 6

so C

Answer 7

be careful with your parentheses

( 4sin(50) )^2

Answer 8

both the 4 and the sin(50) need to be squared

Answer 9

0 = ( 4sin(50) )^(2) + 2(-9.8) * h

Answer 10

like this

Answer 11

yes

Answer 12

i got 0.03

Answer 13

your calculator might be in radians instead of degrees

Answer 14

anyway I end up getting B

wolframalpha.com

enter 0 = (4sin(50))^2 + 2(-9.8)x

Answer 15

yeah i think i used the wrong calc