You kick a ball with a speed of 4 m/s at an angle of 10 degrees. How far away does the ball land? A: 0.40m B: 0.56m C: 0.95m D: 0.79m
there's a simpler approach for this one, we just need to figure out how long the ball spent in the air and then use the x-velocity to calculate the distance so vf = vi + at where vf is 0, vi is the initial velocity in the y-direction, a is the acceleration due to gravity, and solve for t
0=4+-9.8(t)
we have to resolve the velocity into it's y-component, so velocity * sin(theta) not just velocity
4sin(10)
so 4sin(10)+(-9.8)t
good, set that equal to 0 and solve for t
0=4sin(10)+(-9.8)t
i got 0.07
good, so the ball stays up to 0.07 * 2 seconds (since that equation only tells us how long it takes to reach the peak, not the entire distance) so distance = velocity * time this time use the x-direction velocity and time to find the distance
so 0.07*2?
that's the time use that to find the distance in the x direction
0.56
B
awesome
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