Question

Help

Answer 1

@Vocaloid
@dude

Answer 2

Tag me when you are back online.

Answer 3

Here @Shadow

Answer 4

@Vocaloid

Answer 5

horizontal component is velocity * cos(theta)
vertical is velocity * sin(theta)

Answer 6

8.3 * cos(27)=

Answer 7

good now evaluate that

Answer 8

7.4

Answer 9

good, now keep going w/ the vertical component

Answer 10

8.3 * sin(27)

Answer 11

good, evaluate that

Answer 12

3.77

Answer 13

are there any units

Answer 14

these are velocities so the units are...?

Answer 15

m/s

Answer 16

good

Answer 17

use the first kinematic equation to find the time for c)

Answer 18

v=8.3+(9.8)(

Answer 19

we are only interested in the velocity in the vertical direction so use the vertical component of velocity as v initial

Answer 20

so 3.77

Answer 21

yes

remember, at the peak of a curve the velocity is 0

using this information, solve for t

Answer 22

3.77=0+(9.8)(8.3)

Answer 23

the initial velocity is the vertical component of velocity

the final velocity is 0 because we are ending at the top of the curve

Answer 24

when you set up an equation, the variable you are solving for is left as a variable so you have something to solve for

Answer 25

so, since we are solving for t, your equation must have t as a variable not a number

Answer 26

0=3.77+(9.8)t

Answer 27

good (just use -9.8 since the acceleration is downward)

0 = 3.77 + (-9.8)t solve for t

Answer 28

0.38

Answer 29

m/s

Answer 30

what are the units of time?

Answer 31

oh never mind

Answer 32

still there?

Answer 33

Yes

Answer 34

that would be my final answer right

Answer 35

what are the units of time?

Answer 36

seconds

Answer 37

good so 0.38 seconds

Answer 38

cool now for d

Answer 39

use equation 3 to find the vertical distance

remember you must use the vertical component of the initial velocity and a as -g

Answer 40

3.77+1/2(-9.8)t

Answer 41

t^2 not t

Answer 42

plus we already solved for t (0.38 seconds) so you can plug that in for t

Answer 43

3.77+1/2(-9.8)(0.38)

Answer 44

3.77 + (1/2)(-9.8)(0.38)^2 ---> then evaluate this

Answer 45

3.06

Answer 46

good, so that's the max height

Answer 47

e) total time for a parabolic projection is time to the height * 2

so take the answer from part c) and double it

Answer 48

0.76

Answer 49

good

for f) we only need to consider the horizontal velocity

so horizontal velocity = horizontal distance/time, solve for distance

Answer 50

so um 7.4

Answer 51

the horizontal component is 8.3cos(27) m/s

the time is 0.76 seconds

solve for distance

Answer 52

0.76*8.9(cos)27

Answer 53

good, now evaluate that

Answer 54

6.03

Answer 55

you accidentally typed 8.9 instead of 8.3

Answer 56

try this 0.76* 8.3 * cos(27)

Answer 57

5.62

Answer 58

good

Answer 59

that would be m/s

Answer 60

"how far"

what units would this be?

Answer 61

m

Answer 62

good m

Answer 63

for d it would be m/s and e seconds right?

Answer 64

"maximum height"

Answer 65

m

Answer 66

good, e is still seconds