Question

?

Answer 1

first we will find how long it takes to reach the top of the parabola

equation 1 using the vertical velocity only, solve for t

Answer 2

4.3*65?

Answer 3

initial y-velocity = 4.3sin(65)

Answer 4

3.9

Answer 5

good, now plug that into the k-eq and solve for t

Answer 6

which number equation would that be 3 or 4

Answer 7

equation 1

Answer 8

3.9=4.3+ax

Answer 9

we are looking to see how long it takes to reach the top of the parabola

the velocity at the top of the parabola is 0

set final velocity equal to 0
set initial velocity equal to the velocity in the y-direction only

then solve for t

Answer 10

0=3.9

Answer 11

that + at

solve for t

Answer 12

0=3.9+(9.8)t

Answer 13

good just be sure to put a negative sign on a

Answer 14

0.4

Answer 15

good

so the ball stays up for 0.4*2 = 0.8 seconds

now, to find the horizontal distance use

horizontal velocity = horizontal distance/time

solve for horizontal distance

Answer 16

0.8*4.3?

Answer 17

horizontal velocity = ?

Answer 18

4.3

Answer 19

the velocity is being thrown at an angle so you must resolve into its horizontal component

Answer 20

oh 3.9

Answer 21

horizontal and vertical components of velocity (I would recommend writing this down)

horizontal = velocity * cos(theta)
vertical = velocity * sin(theta)

Answer 22

horizontal component = ?

Answer 23

4.3*cos(65)

Answer 24

good

then use that to calculate the distance

Answer 25

1.81

Answer 26

and then 3.9

Answer 27

distance = velocity * time = 4.3*cos(65) * 0.8 sec = ?

Answer 28

it's 1.4

I'm going to bed, gn

Answer 29

SO D