Geometry help
oh whoops I forgot to get back to this ;_; did you end up getting anything as your answer yet?
no i had said that i know it must be irritating t have to explain everything but i honestly dont understand this and im just trying to get through the rest of the year.
so the x-coordinates are -1 and 6, just add these together and divide by 2 to get the new x-coordinate (-1+6)/2 = 2.5 is the new x-coordinate repeat this process w/ the y-coordinates
okay, thank you
would y by 5?
good, so (2.5,5) = your ans
awesome, thank you.
y = (5/4)x - 2 is the original line the perpendicular line will have -4/5 as a slope (we take the original slope, flip the num and denominator, then stick a negative sign in front) so y = (-4/5)x + b you are given a point (10,5), so 10 will be your x-value and 5 will be your y-value, substitute these into the second equation to get b
okay, so would it be y=(10, 5)x+b
y = (-4/5)x + b the -4/5 stays as it is, this is the slope replace "y" with "5" and "x" with 10 and solve for b
oh okay i see now, 5=(-4/5)10+b b=13
good so the new equation is y = (-4/5)x + 13
you'll have to use the pythagorean theorem to figure out the side lengths|dw:1516818026024:dw|
|dw:1516818031792:dw|
c^2 = 3^2 + 2^2 c = ?
hey, sorry my internet went out or something.
and is it 4?
3^2 + 2^2 = ?
13
good, and if c^2 = 13 then c = ? (don't use decimals yet, just leave it in radical form)
6.5?
don't use decimals yet c = sqrt(13)
and how would i do radical form
c^2 = 13, c = sqrt(13) is the radical form since it still has the square root symbol now we repeat the process with the other side
|dw:1516818747279:dw|
c^2 = 6^2 + 4^2 c = ?
52?
c^2 = 52, which means c = sqrt(52) now we just multiply area = length * width = sqrt(52) * sqrt(13) = 26 = your answer
thank you, i'll post the next one
first we draw a line from the point to each vertex of the shape|dw:1516819058735:dw|
|dw:1516819063867:dw|
now we just double the length of each line and draw the new vertices at the new ends
|dw:1516819099855:dw|
okay, thank you.
for each one you have to make sure that, for each corresponding side, the ratio is the same (it's probably easier to show than to explain w/ words)
|dw:1516819363283:dw|
|dw:1516819627996:dw|
first we pick two "corresponding sides" or the "matching" sides from each figure
|dw:1516819681938:dw|
the two slanty sides have a ratio of 30/12 now we pick two other corresponding sides (i'll pick the top side)
|dw:1516819721340:dw|
these have a ratio of 7.5/3 30/12 = 7.5/3 = 2.5, so we have to keep checking to see if ALL corresponding sides have the same ratio
|dw:1516819785669:dw|
all of these are equal to 2.5, which means that the two shapes ARE similar repeat this process for every shape (it's tiresome i know sorry)
Okay
Is this right?
yup good
first try re-drawing them so they are in the same orientation
|dw:1516820383564:dw|
|dw:1516820389195:dw|
now, notice how the points on FSHB are starting from F and going clockwise? to name the other shape we start from K (the corresponding point) and also go clockwise
|dw:1516820449454:dw|
KTWJ
good
thanks :) so thats the answer?
yes
again, let's draw the big triangle in the same orientation as the smaller one
ok
|dw:1516820624803:dw|
|dw:1516820630201:dw|
now we set up a proportion of corresponding sides DY/HS = DL/HK plug and solve for DY
im confused as to how to do that -_-
take a look at the diagram you are given HS, DL, and HK plug those in and solve for DY.
ok
would it be x/32=24/15
good, solve for x
256/5
good, but they want a decimal so convert that to a decimal
ok and sorry im taking long to answer, my mom chooses the most opportune times to interrupt me
51.2
good, that's it
try to re-draw them in the same orientation pick two corresponding sides and then divide them (small side/big side) since we are dilating from big to small let me know if you get stuck
okay
I probably need to get going soon, I can recommend dude, 563blackghost, or shadow as other people who can potentially help
okay, thank you for all your help i really appreciate it. i hope you have a good day :)
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