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Mathematics 8 Online
hardlyhuman:

Geometry help

hardlyhuman:

1 attachment
Vocaloid:

oh whoops I forgot to get back to this ;_; did you end up getting anything as your answer yet?

hardlyhuman:

no i had said that i know it must be irritating t have to explain everything but i honestly dont understand this and im just trying to get through the rest of the year.

Vocaloid:

so the x-coordinates are -1 and 6, just add these together and divide by 2 to get the new x-coordinate (-1+6)/2 = 2.5 is the new x-coordinate repeat this process w/ the y-coordinates

hardlyhuman:

okay, thank you

hardlyhuman:

would y by 5?

Vocaloid:

good, so (2.5,5) = your ans

hardlyhuman:

awesome, thank you.

1 attachment
Vocaloid:

y = (5/4)x - 2 is the original line the perpendicular line will have -4/5 as a slope (we take the original slope, flip the num and denominator, then stick a negative sign in front) so y = (-4/5)x + b you are given a point (10,5), so 10 will be your x-value and 5 will be your y-value, substitute these into the second equation to get b

hardlyhuman:

okay, so would it be y=(10, 5)x+b

Vocaloid:

y = (-4/5)x + b the -4/5 stays as it is, this is the slope replace "y" with "5" and "x" with 10 and solve for b

hardlyhuman:

oh okay i see now, 5=(-4/5)10+b b=13

Vocaloid:

good so the new equation is y = (-4/5)x + 13

hardlyhuman:

1 attachment
Vocaloid:

you'll have to use the pythagorean theorem to figure out the side lengths|dw:1516818026024:dw|

Vocaloid:

|dw:1516818031792:dw|

Vocaloid:

c^2 = 3^2 + 2^2 c = ?

hardlyhuman:

hey, sorry my internet went out or something.

hardlyhuman:

and is it 4?

Vocaloid:

3^2 + 2^2 = ?

hardlyhuman:

13

Vocaloid:

good, and if c^2 = 13 then c = ? (don't use decimals yet, just leave it in radical form)

hardlyhuman:

6.5?

Vocaloid:

don't use decimals yet c = sqrt(13)

hardlyhuman:

and how would i do radical form

Vocaloid:

c^2 = 13, c = sqrt(13) is the radical form since it still has the square root symbol now we repeat the process with the other side

Vocaloid:

|dw:1516818747279:dw|

Vocaloid:

c^2 = 6^2 + 4^2 c = ?

hardlyhuman:

52?

Vocaloid:

c^2 = 52, which means c = sqrt(52) now we just multiply area = length * width = sqrt(52) * sqrt(13) = 26 = your answer

hardlyhuman:

thank you, i'll post the next one

hardlyhuman:

1 attachment
Vocaloid:

first we draw a line from the point to each vertex of the shape|dw:1516819058735:dw|

Vocaloid:

|dw:1516819063867:dw|

Vocaloid:

now we just double the length of each line and draw the new vertices at the new ends

Vocaloid:

|dw:1516819099855:dw|

hardlyhuman:

okay, thank you.

1 attachment
Vocaloid:

for each one you have to make sure that, for each corresponding side, the ratio is the same (it's probably easier to show than to explain w/ words)

Vocaloid:

|dw:1516819363283:dw|

Vocaloid:

|dw:1516819627996:dw|

Vocaloid:

first we pick two "corresponding sides" or the "matching" sides from each figure

Vocaloid:

|dw:1516819681938:dw|

Vocaloid:

the two slanty sides have a ratio of 30/12 now we pick two other corresponding sides (i'll pick the top side)

Vocaloid:

|dw:1516819721340:dw|

Vocaloid:

these have a ratio of 7.5/3 30/12 = 7.5/3 = 2.5, so we have to keep checking to see if ALL corresponding sides have the same ratio

Vocaloid:

|dw:1516819785669:dw|

Vocaloid:

all of these are equal to 2.5, which means that the two shapes ARE similar repeat this process for every shape (it's tiresome i know sorry)

hardlyhuman:

Okay

hardlyhuman:

Is this right?

1 attachment
Vocaloid:

yup good

hardlyhuman:

1 attachment
Vocaloid:

first try re-drawing them so they are in the same orientation

Vocaloid:

|dw:1516820383564:dw|

Vocaloid:

|dw:1516820389195:dw|

Vocaloid:

now, notice how the points on FSHB are starting from F and going clockwise? to name the other shape we start from K (the corresponding point) and also go clockwise

Vocaloid:

|dw:1516820449454:dw|

hardlyhuman:

KTWJ

Vocaloid:

good

hardlyhuman:

thanks :) so thats the answer?

Vocaloid:

yes

hardlyhuman:

1 attachment
Vocaloid:

again, let's draw the big triangle in the same orientation as the smaller one

hardlyhuman:

ok

Vocaloid:

|dw:1516820624803:dw|

Vocaloid:

|dw:1516820630201:dw|

Vocaloid:

now we set up a proportion of corresponding sides DY/HS = DL/HK plug and solve for DY

hardlyhuman:

im confused as to how to do that -_-

Vocaloid:

take a look at the diagram you are given HS, DL, and HK plug those in and solve for DY.

hardlyhuman:

ok

hardlyhuman:

would it be x/32=24/15

Vocaloid:

good, solve for x

hardlyhuman:

256/5

Vocaloid:

good, but they want a decimal so convert that to a decimal

hardlyhuman:

ok and sorry im taking long to answer, my mom chooses the most opportune times to interrupt me

hardlyhuman:

51.2

Vocaloid:

good, that's it

hardlyhuman:

1 attachment
Vocaloid:

try to re-draw them in the same orientation pick two corresponding sides and then divide them (small side/big side) since we are dilating from big to small let me know if you get stuck

hardlyhuman:

okay

Vocaloid:

I probably need to get going soon, I can recommend dude, 563blackghost, or shadow as other people who can potentially help

hardlyhuman:

okay, thank you for all your help i really appreciate it. i hope you have a good day :)

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