Question

?

Answer 1

sorry i went afk >.<

Use the equation \(\large\bf{s=ut + (\frac{1}{2})at^{2}}\)

Answer 2

You would plug in as followed.

s = distance
u = initial velocity
t = time
a = acceleration

\(\large\bf{s=0 \times 0.5 + (\frac{1}{2}) \times 1.5 \times 0.5^{2}}\)

Answer 3

did the equation help @zarkam21

Answer 4

no thank you.

Answer 5

0.1875

Answer 6

correct

Answer 7

SO C

Answer 8

yup

Answer 9

Thank you @563blackghost