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Mathematics 7 Online
zarkam21:

?

zarkam21:

1 attachment
Vocaloid:

a) the velocity vector is tangent to the circle, and since the arm is moving clockwise, we can tell the direction|dw:1516843259816:dw|

Vocaloid:

|dw:1516843266460:dw|

Vocaloid:

b) centripetal acceleration points from the car to the center as usual c) a = v^2/r

zarkam21:

a=26.8^2/14.6

Vocaloid:

good d) 8g just means 8 * g where g is the universal gravity constant

Vocaloid:

anyway for e) just use the acceleration from d) to find the new velocity

zarkam21:

sorry i had to go.... this for c right....a=26.8^2/14.6=49.19

Vocaloid:

good units for acceleration are m/s/s as usual

zarkam21:

D). 8 * 9.8=78.4

Vocaloid:

good

zarkam21:

m/s?

Vocaloid:

the units are given in the problem

zarkam21:

right m/s^2

Vocaloid:

good

zarkam21:

okay now for E

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid anyway for e) just use the acceleration from d) to find the new velocity \(\color{#0cbb34}{\text{End of Quote}}\)

zarkam21:

yes, so i would use 78.4

Vocaloid:

yes

zarkam21:

OKay so the equation would be 4?

Vocaloid:

it's the same centripetal motion problem so a = v^2/r

zarkam21:

got it

zarkam21:

78.4=v^2/8?

zarkam21:

or would it b e equal to 8 maybe?

Vocaloid:

the radius is the same as the radius stated in c)

zarkam21:

got it 78.4=v^2/14.6

Vocaloid:

good

zarkam21:

=33.83

Vocaloid:

good, 33.83 m/s

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