??
21sin(51) 21cos(51)
for a and b
good (remember that cos is the horizontal velocity so that must be a)
(you need to switch them)
a. What is the horizontal component of the velocity? (2 points) 21cos(51)=13.22 b. What is the vertical component of the velocity? (2 points) 21sin(51)=16.32
good for c) use kinematics equation 1 to find the time
* I would recommend writing this down somewhere: at the peak of a parabolic projection the velocity in the y-direction is 0
okay will do
with that in mind, try solving for time
vf = vi + at, plug everything except t in and solve for time
Sorry a little busy,
okay let me plug in the numbers
vf = vi + at 0=16.32+(9.8)t
16.32=0+(9.8)t
you had it right the first time 0=16.32+(9.8)t since the final state is at the top of the parabola, vf is 0 and vi is the initial velocity given in the problem
-1.67
yeah good (if we change 9.8 to -9.8 we should get the positive time value, 1.67 seconds)
for d) use deltax = v_0 * t + (1/2)at^2 to find height
so it would be positive ?
yeah (time can't be negative)
oh yeah lol
okay so d
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid for d) use deltax = v_0 * t + (1/2)at^2 to find height \(\color{#0cbb34}{\text{End of Quote}}\)
okay so deltax=0*t+ (1/2)at^2
@Vocaloid
the initial velocity is not 0 (it's equal to the initial vertical component of velocity) you must also substitute the time value for c) and -g for acceleration
16.32*1.67+(1/2)(-9.8)t^2
you also need to substitute for the other t
16.32*1.67+(1/2)(-9.8)1.67^2
13.59
good for e) the total time is just double the time it took to reach the top so double the answer from c)
1.67*2=3.34 seconds
good for f) the velocity in the x-direction is constant so multiply the x-direction velocity * total time to get distance
13.22*3.34=44.15 m/s
the units of distance are not m/s if you are confused about units there are two ways to clear it up: 1. the units must cancel out m/s * s --> the s cancels out so it is m 2. thinking about what the physical quantity we are looking for is distance is m
okay so distance is m velocity is m/s and time is s
yes
what is m/s/s again?
acceleration
so for height it would be?
m
OKay thanks !!
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