Question

A. 2.37 m/s
?

Answer 1

a) avg speed = distance/time = ?

Answer 2

oh shoot i divided wrong

Answer 3

4.13m/s

Answer 4

good

b) acceleration = (final velocity - initial velocity)/time

Answer 5

(5.3-4)/2=0.65

Answer 6

good, units are m/s/s as usual

Answer 7

anyway, for c) use equation 3: delta(x) = + v_o * t + (1/2)at^2

Answer 8

this would be the same riggt

Answer 9

okay

Answer 10

so

Answer 11

delta(x) = + 13* 21.1+ (1/2)(9.8)(12.1)^2

Answer 12

you are solving for a (we don't use gravity here since the object is only moving horizontally)

Answer 13

it meant 12.1

Answer 14

delta(x) is distance which is already given

Answer 15

yeah that's what i thought

Answer 16

8 =13* 12.1+ (1/2)(a)(12.1)^2

Answer 17

god i'm an idiot that's the wrong equation since you aren't given time

Answer 18

v^2 = v_o^2 + 2a(deltax) sorry

Answer 19

so 4

Answer 20

so 4

Answer 21

okay

Answer 22

0=13+2(a)(x)

Answer 23

well 13^2

Answer 24

good, don't forget to plug in delta x and solve for (a)

Answer 25

-13/16

Answer 26

-0.81

Answer 27

0=13+2(a)(8)

Answer 28

i did this equation with x as the distance given which is 8

Answer 29

needs to be 13^2

0=13^2+2(a)(8)

Answer 30

oh ugghh

Answer 31

-10.56

Answer 32

good units are m/s/s as usual

acceleration is negative since he's slowing down

Answer 33

thanks I'm starting to get better at it now !