?
100 N to the left 175 N to the right what is the net force?
A
✓
so it only wants the x-direction so there are only two relevant forces - the pedalling force + the air resistance 400N pedalling to the right 300N resisting air force to the left what's the net?
A
good
knowing that this would be C?
force of gravity = mg force of gravity - air resistance = ?
B
good
do you know how you would sketch the Free body diagram for this situation?
it would definitely be a slope
have to be careful here - it doesn't say the sled is on a slope, the sled is not on an angle but the force is
|dw:1516946174954:dw|
|dw:1516946128810:dw|
oh okay so I'm wrong then here right
|dw:1516946216680:dw|
then the angled force (25 deg 30N)|dw:1516946255961:dw|
now, if you remember our decomposition formulas: horizontal force = force * cos(theta) vertical force = force * sin(theta)
|dw:1516946306953:dw|
in the y-direction we have: Fsin(theta) pointing up Fnormal pointing up Fg pointing down so Fsin(theta) + normal force - weight force = 0 (since no movement in the y-direction) you can plug F , theta, and gravity into the equation to solve for the normal force
F is the applied force (30N) theta is the angle (25 degrees) Fg = mg
C
good
D?
similar formula (y-component --> vertical component --> Tension* sin(theta))
good, d
A?
the man is not moving in the y-direction so normal force and gravity cancel out normal force = gravity force = ?
good, A
Have no idea on this one
|dw:1516947766517:dw| N = mgcos(theta), choice C (to derive this you have to use a bit of trigonometry, can explain some other time)
|dw:1516947950055:dw|
C?
good
Join our real-time social learning platform and learn together with your friends!