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Mathematics 10 Online
vaporeon246:

Please help

vaporeon246:

If x is a positive number, then \[\sqrt[5]{x}\div x ^{1/5}\]

vaporeon246:

Equals what?

sillybilly123:

\(\sqrt[5]{x}= x ^{1/5}\) does that help?

vaporeon246:

no sorry @sillybilly123 answer choices a) x^5 b) 1/5x c) 1 d) 1/5

sillybilly123:

read it again: \(\sqrt[5]{x} \color{red}{=} x ^{1/5}\)

vaporeon246:

but it's not one of the answer choices

sillybilly123:

i'm NOT feeding you an answer. but i am telling you that the numerator and denominator are exactly the same go figure if you wanna get smarter

vaporeon246:

OH wait i see what you mean now @sillybilly123

sillybilly123:

cool!!!!

vaporeon246:

i plugged in 1 for the "x" in both equations and got 1 as the answer

sillybilly123:

i'm trying to tell you that: \(\sqrt[5]{x}\div x ^{1/5}\) is the same as \(x ^{1/5}\div x ^{1/5}\) and \( \sqrt[5]{x} \div \sqrt[5]{x}\) because \(\sqrt[5]{x} \color{red}{=} x ^{1/5}\) by definition you have merely solved this for x =1. so solve \(x + 1 = 2x\). Well that works for \(x = 1\) so it must always be true. NOT :( let x = 7

sillybilly123:

if i'm not making sense to you, vap, my apologies; and we need Special Agent Voca on this one. I am a terrible teacher :( @Vocaloid

vaporeon246:

so you're saying x + 1 = 2x -2x -2x -x +1 = 0 -1 -1 -x = -1 divide both sides by -1 and x = 1, Right?

sillybilly123:

yes. it works if x = 1 does it work if x = 37 ?!

vaporeon246:

no

sillybilly123:

do you get that \(\sqrt[5]{x} = x ^{1/5}\) ?? they are the same thing

sillybilly123:

just different symbology

vaporeon246:

yes

sillybilly123:

brill!

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