A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 2x + 4z = 1 Which of the following is a possible step used in eliminating the z-term? Also, as I said before, could you explain your answer? Thanks guys >_< Multiply equation B by 4. Multiply equation A by 2. Multiply equation A by –4. Multiply equation B by 2.
The way that elimination works is that you add the two equations together. However, before you do so, you want to make sure that by doing so, a variable is eliminated. Here we want to eliminate z. Due to like terms, only z terms will be able to add by each other. We have z on the top equation, and 4z on the bottom equation. In order to make 4z zero, we must subtract by 4z. So if we add -4z to positive 4z, we will get zero. In order to get -4z on the top equation, what must we do to the top equation.
umm not quite sure :/
Example. 2a + b = 2 6a + 8b = 10 I want to eliminate 8b. So I multiply the top equation by -8 \[-8(2a + b = 2) \] \[-16a -8b = -16\] Now if I add the two equations, -8b and +8b cancel each other out.
Yes so we are left with the b?
from the 8s
No. \[8b + (-8b) = 0\]
Or \[8b - 8b = 0\] Same thing.
It's basically 8 of something minus 8 of the same thing.
Does that make sense to you?
yes it does
So what can we do to Equation A: x + z = 6, in order to take out the 4z on the bottom equation.
hmm
well if we ultiply the 2 by 2
by -2*
we would get -4 right?
and then the 4's cancel eachother out?
so z = 1?
@Shadow
ar you there??
No that's incorrect Multiplying by -2 would cancel x out and Shadow said to cancel z out
oh ok
so what would I have to do?'
What could you multiply x + z = 6 with so that 4z in the second equation gets taken out?
6?
I am not good at math >_<
If you multiply the first equation by 6: x + z = 6 -> 6x + 6z = 36 And then your second equation is 2x + 4z = 1 If you add them together 6x + 6z = 36 +2x + 4z = 1
8x + 10z = 37 The z is still there it didn't get canceled out
oh
I'm not sure
It would be -4 -4x - 4z = -24 + 2x + 4z = 1
-2x + 0 = -23 Then you solve for x -2x = -23 -23/-2 = ?
11.5?
Yes
Now in either equation you can plug 11.5 for x We'll use the first one x + z = 6 11.5 + z = 6 Solve for z
-5.5?
Yep Your question doesn't require to solve for this but I'm just showing you for later use
So back to your question
What did we do to x + z = 6 to get rid of z
multiplied by -4
So option C)
ok thx :D
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