Question

Help please

Answer 1

some hints:

half-life implies Q(t) = (1/2)Q0

plug in t = 6,300 and solve for k

Answer 2

A

Answer 3

awesome

Answer 4

Q(t) is the final amount (12g)
Q0 is the initial amount (36)
k is the decay constant (0.00011)

solve for t, you'll have to use a calc for this one

Answer 5

2=36e^(-0.00011t)

Answer 6

12 not 2 but otherwise good

Answer 7

D

Answer 8

awesome

Answer 9

which of the following graph represents exponential decay

Answer 10

Prob A?

Answer 11

oh right yeah A (was working on some proofreading for another user)

Answer 12

P(h) = 0.85 * P0

solve for h

Answer 13

wait it doesn't want you to solve it it just wants you to set up the equation

Answer 14

C

Answer 15

or maybe a

Answer 16

P(h) = 0.85P0

just replace P(h) with 0.85P0 in the original eq and leave everything else alone

Answer 17

So um C

Answer 18

wait just setting up the equation right?

Answer 19

0.85Po = Poe^(-0.00012h) so B

Answer 20

would probably just chuck this into a graphing calculator/demos/whatever

Answer 21

i git b and a

Answer 22

https://www.desmos.com/calculator

Answer 23

for A) you just need to check that P(t) 5.74 when t = 1

for B) not sure

for C) as t ---> infinity , P(t) converges to 64 so yes

for D) no it levels off

so yeah I would at least guess C + A

Answer 24

Yeah i got c and a i think that's it

Answer 25

thanks

Answer 26

the graph pretty much takes the same shape as the last one

Answer 27

so A) no the rate will eventually level off since there are only a finite number of people who can potentially hear the rumor

B) a bit uncertain about this one, since 299e^(-0.36t) never actually reaches 0 the entire function never actually reaches 300 implying there are less than 300 people available to hear the rumor, so 299 makes sense (depends on whether they round up or down tho)

C) plugging in t = 0 gives us 300/300 = 1 so yes

D) let t = 14 and see if the entire function equals 100

Answer 28

anyway I should probably go to sleep after you finish D

Answer 29

So c d

Answer 30

goodnight =) Thanks again