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Vocaloid:
try to think back about function transforms -
how does f(x+h) compare to f(x) visually?
zarkam21:
well they bounce off each other right? :/
Vocaloid:
|dw:1517362490796:dw|
zarkam21:
OKay so sifted left
zarkam21:
shifted
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Vocaloid:
good, so that means it looks like the graph of f(x) = x^(1/5) shifted left a bit
what does multiplying the entire function by -1 do? (visually)?
zarkam21:
well b is the most shifted to the left
Vocaloid:
|dw:1517362678696:dw|
Vocaloid:
given this information, take the graph of f(x) = x^(1/5) and then reflect across the x-axis while shifting it to the left, and select the graph that matches
zarkam21:
C
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zarkam21:
actually a
Vocaloid:
you had it right the first time (B) just wanted to make sure you understood why ^^"|dw:1517362898928:dw|
Vocaloid:
|dw:1517362914163:dw|
Vocaloid:
|dw:1517362928114:dw|
zarkam21:
I have the original graph up so i was just looking at which was shifted left .. how would i know for sure
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zarkam21:
Oh okay so it is the same graph just shifted
Vocaloid:
process of elimination
it has to be reflected across the x-axis too which eliminates C and B
can't be D either b/c the domain isn't restricted
zarkam21:
got it ,, so it had to be reflected across the x-axis .. i think that is the point i missed
Vocaloid:
yup, the original equation has a negative sign in front of the equation so it has to be reflected across x
zarkam21:
GOt it thanks!
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look for the functions where there is not a constant ratio between terms
zarkam21:
C
Vocaloid:
notice how each term in k(x) is being divided by 4 each time making this an exponential function
the question is asking for which ones aren't exponential
zarkam21:
A def
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zarkam21:
B>>??
Vocaloid:
A actually is an exponential function (it's doubling each time)
B counts; h(x) does not have a constant ratio
D also counts (notice how the ratio changes near the end)
so B+D