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Mathematics 18 Online
zarkam21:

Help

zarkam21:

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zarkam21:

@Vocaloid

zarkam21:

@Zepdrix

Vocaloid:

you're given every value except for r in the formula, you just need to plug them in and solve for r

zarkam21:

A

zarkam21:

2543=2000^(r(4))

Vocaloid:

you forgot the e

Vocaloid:

2000*e^(rt)

zarkam21:

well t would be 4 right

zarkam21:

because it is the time

Vocaloid:

e is not the time e is a constant that has its own value t is the time

zarkam21:

Yeah lol that's what i said ^~^

zarkam21:

2000*e^(r)(4)

Vocaloid:

good, now solve for r (be very careful with your parentheses)

Vocaloid:

the exponent needs to be enclosed in parentheses e^(4r)

zarkam21:

all equal to 2543

Vocaloid:

yes

zarkam21:

B

Vocaloid:

good

zarkam21:

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Vocaloid:

you are given the final height P(h) = 0.65 * P_0 solve for h

zarkam21:

would i substitute anything for P_O

Vocaloid:

when you write out the equation you will see why you don't need anything for P_0

Vocaloid:

0.65 * P_0 = P_0 * e^(-0.00012h) solve for h notice why we don't need a P_0 value

Vocaloid:

|dw:1517362017394:dw|

zarkam21:

D

Vocaloid:

good

zarkam21:

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zarkam21:

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zarkam21:

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Vocaloid:

try to think back about function transforms - how does f(x+h) compare to f(x) visually?

zarkam21:

well they bounce off each other right? :/

Vocaloid:

|dw:1517362490796:dw|

zarkam21:

OKay so sifted left

zarkam21:

shifted

Vocaloid:

good, so that means it looks like the graph of f(x) = x^(1/5) shifted left a bit what does multiplying the entire function by -1 do? (visually)?

zarkam21:

well b is the most shifted to the left

Vocaloid:

|dw:1517362678696:dw|

Vocaloid:

given this information, take the graph of f(x) = x^(1/5) and then reflect across the x-axis while shifting it to the left, and select the graph that matches

zarkam21:

C

zarkam21:

actually a

Vocaloid:

you had it right the first time (B) just wanted to make sure you understood why ^^"|dw:1517362898928:dw|

Vocaloid:

|dw:1517362914163:dw|

Vocaloid:

|dw:1517362928114:dw|

zarkam21:

I have the original graph up so i was just looking at which was shifted left .. how would i know for sure

zarkam21:

Oh okay so it is the same graph just shifted

Vocaloid:

process of elimination it has to be reflected across the x-axis too which eliminates C and B can't be D either b/c the domain isn't restricted

zarkam21:

got it ,, so it had to be reflected across the x-axis .. i think that is the point i missed

Vocaloid:

yup, the original equation has a negative sign in front of the equation so it has to be reflected across x

zarkam21:

GOt it thanks!

zarkam21:

D?

zarkam21:

1 attachment
Vocaloid:

first split the log into its components using log rules 1 + 2|dw:1517363260049:dw| lmk if you get stuck

zarkam21:

rule 1 (3^5*2^2)=log b 243 + 2

zarkam21:

like this rigght

Vocaloid:

don't look at the numbers at the top just focus on decomposing this part|dw:1517363410029:dw|

Vocaloid:

|dw:1517363417929:dw|

Vocaloid:

if it helps just focus on the numerator first logb(M*N) = logb(M) + logb(N) logb(A^5 * C^2) = ?

zarkam21:

log(b)+5log(a)+2log(c)

Vocaloid:

you don't need that log(b) at the beginning logb(A^5 * C^2) = logb(A^5) + logb(C^2)

Vocaloid:

then repeat the process to write the expression for the denominator

zarkam21:

log b (D^6)

Vocaloid:

|dw:1517363677009:dw|

Vocaloid:

good, now we just bring the exponents down like so:|dw:1517363738720:dw|

Vocaloid:

sorry if that's messy but it's just 5logb(A) + 3log(C) - 6logb(D) then we just replace the values given in the original problem

Vocaloid:

|dw:1517363799937:dw|

Vocaloid:

|dw:1517363809272:dw|

Vocaloid:

so -11 = your ans

zarkam21:

Thank you for all that

zarkam21:

155/8?

zarkam21:

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Vocaloid:

nvm yeah 155/8 is right

zarkam21:

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zarkam21:

B

zarkam21:

ANd C

zarkam21:

because a and d have -5

Vocaloid:

yeah good

zarkam21:

a,b,c

zarkam21:

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Vocaloid:

remember that for geometric each term has to be ~multiplied~ by a term not added so one of those doesn't work

zarkam21:

a and c

Vocaloid:

good, a and c but not b or d

zarkam21:

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Vocaloid:

combine the two logs on the left into one log (it's log rule 1 or 2 I don't remember)

zarkam21:

C

Vocaloid:

yeah good C

zarkam21:

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zarkam21:

A and C

Vocaloid:

D is also false (should be a minus sign not a divsion sign on the right so ACD

zarkam21:

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zarkam21:

I'm getting no solution

Vocaloid:

either be careful with your parentheses (exponents need their own parentheses) or solve by hand

zarkam21:

500=25e^(2x)

Vocaloid:

divide both sides by 25, take the natural log to eliminate e, then isolate for x

zarkam21:

isn't it supposed to be like this

Vocaloid:

yeah that's fine

Vocaloid:

mathway can be stupid sometimes so I prefer wolframalpha (even thought that can be dumb sometimes too)

Vocaloid:

still there?

zarkam21:

Yes i am here

Vocaloid:

any progress yet?

zarkam21:

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Vocaloid:

it's decomposing the log into smaller logs just start with e^(2x) = 20 take the natural log of both sides then isolate x

zarkam21:

so c

Vocaloid:

gud

zarkam21:

which of the following statements are true?

zarkam21:

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zarkam21:

B,C,D

Vocaloid:

gonna say no on D because even radicals and odd radicals behave very differently esp on the domain

Vocaloid:

so just B +C

zarkam21:

A

zarkam21:

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Vocaloid:

log M has to be the bigger one

zarkam21:

D

Vocaloid:

good

zarkam21:

C And D

zarkam21:

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Vocaloid:

look for the functions where there is not a constant ratio between terms

zarkam21:

C

Vocaloid:

notice how each term in k(x) is being divided by 4 each time making this an exponential function the question is asking for which ones aren't exponential

zarkam21:

A def

zarkam21:

B>>??

Vocaloid:

A actually is an exponential function (it's doubling each time) B counts; h(x) does not have a constant ratio D also counts (notice how the ratio changes near the end) so B+D

zarkam21:

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Vocaloid:

good

zarkam21:

C

zarkam21:

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Vocaloid:

check again|dw:1517369892459:dw|

zarkam21:

B

Vocaloid:

good , b

Vocaloid:

can we open a new question this one is lagging

zarkam21:

Sure

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