trig help
@Vocaloid
so a ?
You can use the identity \[ \sin ( \theta ) = \cos ( \pi/2 - \theta ) \]Then plug in \[ \sin ( 4 \pi /3 ) = \cos ( \pi/2 - 4 \pi/3) = \cos( - 5 \pi/6) \] And then use the fact that $$ \cos ( -\theta) = \cos \theta $$
@moreso I'm confused on what question you are solving for?
number 2.
is 2 a?
I don't want to give out a direct answer.
because of identity
what about 3
my notes says tan is positive in 3
whoops, i mean tan and cos are negative in quadrant 2
students sin positive quad 2 all all positive quad 1 take tan positive quad 3 calculus cos positive quad 4
which of those angles is a quadrant 2 angle
so 110 would be answer right/
yep based on unit circle
"all students take calculus " ^ i like that
made 100 on practice yay
good job ;p
@moreso
@Shadow
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c?
Try Pythagorean theorem to find the third side
Then use the reference angle.
$$ \tan \theta = \tan ( \theta ~') $$
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b duh i did hypotenuse instead of opposite and adjacent oops
;p
4?
thats one of them, cos is also positive in which quadrant
1 because of all
yep
omg ty 100 again
:)
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