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Mathematics 8 Online
kaylak:

trig help

kaylak:

@Vocaloid

1 attachment
kaylak:

so a ?

moreso:

You can use the identity \[ \sin ( \theta ) = \cos ( \pi/2 - \theta ) \]Then plug in \[ \sin ( 4 \pi /3 ) = \cos ( \pi/2 - 4 \pi/3) = \cos( - 5 \pi/6) \] And then use the fact that $$ \cos ( -\theta) = \cos \theta $$

kaylak:

@moreso I'm confused on what question you are solving for?

moreso:

number 2.

kaylak:

is 2 a?

moreso:

I don't want to give out a direct answer.

kaylak:

because of identity

kaylak:

what about 3

kaylak:

my notes says tan is positive in 3

moreso:

whoops, i mean tan and cos are negative in quadrant 2

kaylak:

students sin positive quad 2 all all positive quad 1 take tan positive quad 3 calculus cos positive quad 4

moreso:

which of those angles is a quadrant 2 angle

kaylak:

so 110 would be answer right/

kaylak:

yep based on unit circle

moreso:

"all students take calculus " ^ i like that

kaylak:

made 100 on practice yay

moreso:

good job ;p

kaylak:

@moreso

1 attachment
kaylak:

@Shadow

moreso:

|dw:1517424609478:dw|

kaylak:

c?

moreso:

Try Pythagorean theorem to find the third side

moreso:

Then use the reference angle.

moreso:

$$ \tan \theta = \tan ( \theta ~') $$

moreso:

||dw:1517425084181:dw|

kaylak:

b duh i did hypotenuse instead of opposite and adjacent oops

moreso:

;p

kaylak:

4?

moreso:

thats one of them, cos is also positive in which quadrant

kaylak:

1 because of all

kaylak:

yep

kaylak:

omg ty 100 again

moreso:

:)

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