Question

help please

Answer 1

@Vocaloid

Answer 2

since we want to convert from moles Fe to moles CO2 pick the tile that has the ratio between these two compounds, in moles only

Answer 3

it's the tile that has moles Fe and moles CO2.

Answer 4

so something with 3?

Answer 5

since you have 2.9 mol Fe in the numerator, you need to also flip the Co2/Fe tile so that moles of Fe are in the denominator, which will allow us to cancel out the units of Fe

Answer 6

since we are now in moles CO2 and we want volume of CO2, select the tile that gives you the ratio between moles CO2 and volume CO2

Answer 7

select the tile that has moles of CO2 and volume of Co2.

Answer 8

okay

Answer 9

i did and it crossed it out

Answer 10

that's the tile that needs to be added to the answer at the bottom

you should have gotten 1 mol CO2/22.4L CO2 as the tile

now we flip that tile to get 22.4L CO2/1 mol CO2 so we can eliminate the units mol CO2 and get L CO2

Answer 11

the tiles are now in the correct order, to get the numerical answer just multiply the numerators and then divide by the denominators

so 2.9 * 3 * 22.4/2 ---> simplify to get the numerical answer

Answer 12

i got 97.44

Answer 13

that right?

Answer 14

good, and if they care about significant figures round that to 97 L (since we are only given 2 sig figs for 2.9)

Answer 15

they just want the answer unit and the solution

Answer 16

go with 97 L then

Answer 17

next question?

Answer 18

sure

Answer 19

first step is to convert from g iron (III) oxide to moles iron (III) oxide to select the appropriate tile for these two quantities

Answer 20

*so select

Answer 21

that tile would be?

Answer 22

didnt know why that took so long to load..

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
first step is to convert from g iron (III) oxide to moles iron (III) oxide to select the appropriate tile for these two quantities
\(\color{#0cbb34}{\text{End of Quote}}\)

the tile needs to have both moles of iron (III) oxide and g iron (III) oxide, since we are converting between these two values

Answer 24

the two quantities we want are moles iron(III) oxide and grams iron(III) oxide

select the tile that contains these two quantities.

Answer 25

the top middle one?

Answer 26

those are both moles

one side needs to be moles and the other side needs to be grams

Answer 27

ah, third row third down?

Answer 28

both of them need to be iron (III) oxide not just iron

as a reminder the formula for iron(III) oxide is Fe2O3

Answer 29

first row third down?

Answer 30

thats gotta be it

Answer 31

awesome, now since we have 3.8g iron (III) we need to flip that tile so that grams of iron (III) is in the denominator and we can cancel out units

Answer 32

now we need to go from moles Fe2CO3 to moles iron (Fe)

so we need the tile with moles Fe + moles Fe2CO3

Answer 33

that was the top middle one right?

Answer 34

good, since the moles of Fe2CO3 are in the denominator in the tile we don't have to flip this one

Answer 35

now we just need to go from moles Fe to g Fe, select the right tile

Answer 36

a fourth one?

Answer 37

third row third across

Answer 38

we need to flip it so units cancel

Answer 39

so we just multiply/divide as if these were just normal fractions

so (3.8 * 2 * 55.8)/159.78 ---> simplify and that's it

Answer 40

okay, i got it, 2 more questions

Answer 41

sure

Answer 42

this is a simpler one

moles CO --> moles Fe

so select the tile that has both these quantities

Answer 43

first row second down

Answer 44

oh, that was it.

Answer 45

okay, last question

Answer 46

first step is grams Iron (Fe) to moles iron (Fe) ---> pick the tile

Answer 47

third row third down

Answer 48

good, and we need to flip that tile so grams are in the denominator

Answer 49

now, moles Fe --> moles CO

select the appropriate tile

Answer 50

first row second down

Answer 51

good, now we flip that to get

Answer 52

now it's moles CO --> molecules CO --> tile?

Answer 53

okay

Answer 54

if you want to help me with more, that would be nice, but it's okay if 4 was enough

Answer 55

I'm still free, if you still need help I'm willing to help

Answer 56

okay, i might need to make a new question