Question

Find the inverse of the function.

f(x) = 6x3 - 8

f-1(x) = cube root of x divided by six plus eight
f-1(x) = cube root of quantity x minus eight divided by six border=
Not a one-to-one function
f-1(x) = cube root of quantity x plus eight divided by six

Answer 1

@JustSaiyan

Answer 2

I suck at math. I think Vocaloid will be on soon, though. If my stalker abilities are right, she should be on just before Ultri.

Answer 3

Ok no prob man thanks anyways!

Answer 4

Here this should help you learn on how to do the problem, but then also Mathway is a good helping answer math problems! https://www.mathway.com/popular-problems/Precalculus/422679

Answer 5

f of x equals four divided by x. and g of x equals four divided by x

Answer 6

Is your equation
\(f(x) = 6x^3 - 8\)?

Answer 7

@dude can you help with one more

Answer 8

That was not the answer, I was asking if that was the equation in the question

Answer 9

in the question its f(x) equals four divided by x. and g(x) equals four divided by x

Answer 10

the question is Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @SourMunchkin7806
in the question its f(x) equals four divided by x. and g(x) equals four divided by x
\(\color{#0cbb34}{\text{End of Quote}}\)
\(f(x)=\frac4x\\
g(x)=\frac4x\)?
Your question is confusing

Answer 12

yes tahts the equation

Answer 13

so the questions is Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x

Answer 14

thats all it gives me

Answer 15

But f(x) and g(x) are the same equation, that is throwing me off

Answer 16

i know i dont have anything else to give im confused too

Answer 17

@Vocaloid

Answer 18

\(f(g(x)) = x ~~~~\color{green}{f(x)=\frac4x~~~~g(x)=\frac4x}\)

\(\large{f(x)=\frac{4}{\boxed{\frac4x}}}\)

Answer 19

so what would it be?

Answer 20

\[\frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}\\
=\frac{4x}{4}
=x\]

Answer 21

so yes they are inverses?