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GlockParrot69:

Physics Question, Please help me! :) https://image.prntscr.com/image/E3izehX3T4q4PcuEseTt0w.png

Ultrilliam:

@563blackghost

Tyler:

hey parrot

GlockParrot69:

hi :)

GlockParrot69:

please call me "glock" :)

Tyler:

k glock

Tyler:

i have no idea

Tyler:

im sorry

GlockParrot69:

that's ok papi :)

Tyler:

say wha

GlockParrot69:

nothing :)

Tyler:

:b

Tyler:

i think it is -1.00

GlockParrot69:

how do you calculate distance in negative integers?

GlockParrot69:

so basically i have to calculate the whorizontal distance from the very moment the ball begins to fall back to earth from its point of vertex.

Tyler:

yeah basically

GlockParrot69:

|dw:1517871545344:dw|

Vocaloid:

|dw:1517931413940:dw| use kinematics equation 3, except we are working in the y-direction first the initial velocity in the y-direction is 10.0sin(theta) and deltax is the height, 1.00 m, then solve for time now, since that only gives the time taken to reach the peak, we double that to get the total time then, to find the total distance in the x direction, it's (initial velocity in x)*(time)

GlockParrot69:

1 attachment
GlockParrot69:

1 attachment
GlockParrot69:

@AngeI

GlockParrot69:

the second time i tried, i got 17.68 meters

Vocaloid:

I got something a little different (rounding perhaps) 1 = sin(42)*t + (1/2)(-9.8)*t^2 t = 1.19476 seconds 2 * t = 2.3895 seconds time * velocity in the x direction = 2.3895 * 10 * cos(42) = 17.76 m

GlockParrot69:

yeah that's what i got when i tried the second time voca

GlockParrot69:

it'd take me 3 centuries to upload my new solution but yeah i got the same answer as yours.

GlockParrot69:

btw voca are you sick?

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