http://prntscr.com/ibg62h
first, you will graph the lines as if they were regular lines not inequalities. Then we will modify the lines + add shading to indicate the direction of the inequality start by graphing y = -6x - 2 as normal
if you are having trouble with this step let me know
can you show me how it would be on the graph please?
alright, let's do a quick review of how to graph y = mx + b equations m is the slope, b is the y-intercept so for y = -6x -2 slope is -6 and intercept is -2
let's start by putting (0,-2) on the graph since that's the intercept
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since the slope is 6, let's go up 6 units and to the right 1 unit
connect the lines like so:
johnn can you try graphing y = -10 + 5x using the same method?
and theres supposed to be a shaded part to the graph...where will that be?
let's just take care of the lines first what does the graph of y = -10 + 5x look like? can you try drawing it?
the more you participate, the faster this can get done
if you're having trouble I'm happy to help but you need to say something
I have all the lines correct, now i just need the shading
ok, since the first two inequalities are > they need to be dashed lines (not solid) and both lines need to have shading in the region above them
y <= 0 needs to have shading below it
can you show me visually?
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the solution should be emphasized, which is this little part right here|dw:1518021339520:dw|
so the whole bottom part has to be shaded?
yes (shade the whole bottom part lightly (if that's possible) then shade the solution darkest)
okay thank you
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