What is (f+g)(x)? f(x)=x3−x g(x)=x3+2x2−10
(f+g)(x) just means add f(x) and g(x) so let's start with combining the only like terms there are x^3 + x^3 = ?
x^6 i think bc 3+3
that's a good guess but not quite ^^ it's really no different than adding two objects, object + object = 2 objects so x^3 + x^3 = 2x^3
ohh okay
*** - 10 not + 10
2x^3 + 2x^2 - x - 10 = your answer [there's no edit button]
oh okay so just minus 10 instead of +
at the end
yup
alright thx so much !
so would it be the same thing if it was (f*g)(x) instead of (f+g)(x)? @Vocaloid
What is (f⋅g)(x)? f(x)=x2+2x−6 g(x)=x4+3
x^2+x^4 would it be like 2x^6 or adding the exponents
the ⋅ means multiply so you would have to multiply (x^2+2x−6)(x^4+3) using the distributive property, know how to start w/ this?
oh would it be like foil
sort of but the first parentheses have 3 terms so it's a bit different than foil
let's just start with the first term what's x^2 * x^4 = ?
x^6?
is it x^6+2x-18
bc 2x doesn't have a like term and then -3*6 = -18
since we're multiplying we have to consider all terms unfortunately
oh ok oops
multiplying the first terms gives us x^6 multiplying the next terms gives us 2x^3 then we need to keep going |dw:1518045171672:dw|
*** should be 3x^2
|dw:1518045230768:dw|
oh ok so every term in the first paratheses multiplies by every term in the second one
yeah, then the last term in the first parentheses * every term in the second parentheses
|dw:1518045360651:dw|
then just putting everything together: x^6 + 3x^2 + 2x^5 + 6x - 6x^4 - 18 then just re-arrange so that the exponents decrease from highest to lowest x^6 + 2x^5 - 6x^4 + 3x^2 + 6x - 18 = your final answer
okay thanks again if i could give you another medal i would lol
"What is (f⋅g)(x)?" This is a composition. - That is, if you intend that (f⋅g)(x) be \((f \circ g)(x)\) - Then: \((f \circ g)(x) = f(g(x))\)
I thought of that possibility but doesn't a closed dot usually indicate multiplication? :S
it surely does
i was over -thinking it :(
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