http://prntscr.com/icjisn who here is good at math?

Question

Comerpickles · Answer

@Ultrilliam

Ultrilliam · Answer

it appears @shadow is the only one online right now

Comerpickles · Answer

@Shadow

Ultrilliam · Answer

@563blackghost <-- forgot about her

563blackghost · Answer

What answer do you think it is @Comerpickles

Comerpickles · Answer

I was thinking D, but wasn't sure

563blackghost · Answer

We we have given of two sides that are equal to each other, and we find that two angles are equal as well, but progressing in the chart we prove two other angles (not sides) so it would not be by SAS congruency.

It would be `AA Similarity Postulate` with the proving of $\bf{\angle A \cong \angle A}$ and $\bf{\angle ACD \cong \angle ABE}$ as well as $\bf{\angle ADC \cong \angle AEB}$ we see that two angles have been proven equal to two other angles. If they are equal then the last angle is concluded to be equal as well.

Comerpickles · Answer

Okay, thanks sir. Can you help with this one also? Last one http://prntscr.com/icjpjv

563blackghost · Answer

she* ;)

let meh look at it...

Comerpickles · Answer

Ohhhh, apologies

563blackghost · Answer

its okie :3

563blackghost · Answer

Angles that are across from each other are congruent by `Vertical Angle Theorem`.

$\large\bf{\angle 1 ~and~ \angle 4}$ are vertical angles, so they are congruent.

Angles that lie on the same side of the transversal are congruent as well. This is proven by `Corresponding Angles Postulate`.

$\large\bf{\angle 1 ~and~ \angle 5}$ lie on the same side of the transversal, so they are congruent to each other.

It would be `A`.

Comerpickles · Answer

Thank you Ma'am

563blackghost · Answer

np :D