Please Help Algebra 2

Question

vaporeon246 · Answer

Use $$\log_{12} 3 \approx 0.6826 and   \log_{12} 7 \approx 0.7831 \to approximate the value of each exression  $$

vaporeon246 · Answer

4) $$\log_{12} 36  $$
5) $$\log_{12} 63  $$
6) $$\log_{12} 27/49 $$
9) $$\log_{12} 441 $$

Ultrilliam · Answer

All our math helpers seem to be burried under schoolwork right now except for @dude who is probably busy for the next 30 minutes to a hour

and @563blackghost who is AFK ATM x.x

Shadow · Answer

Can you solve the second one?

Shadow · Answer

@vaporeon246

vaporeon246 · Answer

i can try

Shadow · Answer

You understand the concept of these problems, right? It's just using the properties of logarithms to break a log down to logs that we know the values of.

vaporeon246 · Answer

yes i do @Shadow

Shadow · Answer

$$\log _{12} \frac{ 7 }{ 3 } = \log _{12} 7 - \log _{12} 3$$

vaporeon246 · Answer

I was thinking that but i thought it would be wrong

Shadow · Answer

Yeah, these a pretty straightforward if you understand logs. If they are still a touchy topic for you, try view this: https://www.khanacademy.org/math/algebra2/exponential-and-logarithmic-functions/properties-of-logarithms/v/introduction-to-logarithm-properties As Jay said, many of us are busy today. Got two AP quizzes next period c;

Shadow · Answer

Would help if I had the time @vaporeon246

vaporeon246 · Answer

That's ok  @Shadow

vaporeon246 · Answer

here's a somewhat better picture https://mail.google.com/mail/u/0/#inbox/1618c588e3fa17c6