Help?
highest exponent is 3, so only 3 possible total roots to figure out how many complex roots, first figure out how many real roots by setting the equation equal to 0, factoring it, and solving for x
3?
good, so 3 roots [just did a quick search and "zeros over the set of complex numbers" doesn't mean complex roots, just total roots, so part A) is 3]
part II) number of extrema = degree of the function - 1 = ?
2
good for part III) what happens to the function x gets infinitely large and positive? does it diverge to +infinity or -infinity?
+?
good so a) = +infinity what about b)? does the function approach + or -infinity as x --> -infinity?
-
-infinity?
good so b) -infinity
for part IV) use the rational root theorem start by listing all the factors of the constant term 4, including +/- signs for each factor
so +1,+2,+3,+4
3 is not a factor of 4 so ±1, ±2, ±4 then, the leading coefficient is just 1, so its factors are just ±1 then we list all possibilities of constant factors/leading coefficient factors
so ±1/1, ±2/1, ±4/1, then we just simplify this to get ±1, ±2, ±4
for part V) x^3 - x^2 - 4x + 4 start by splitting this into two parts (x^3 - x^2) - (4x - 4) then just factor out the from this and lmk what you get (x^3 - x^2)
*factor out the gcf
x^2(x-1)
awesome then the other part: (4x - 4) factor out the gcf again
4(x-1)
good then we have x^2(x-1) - 4(x-1) we can re-combine these to get (x^2 - 4)(x-1) {this is the opposite of the distributive property] then, if we look at x^2 - 4 this is a difference of squares so what does x^2 - 4 factor to?
(x+2)(x-2)
awesome so the entire factored form is (x-1)(x+2)(x-2) = your ans
and that's it!
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