@Shadow
How do you think we should approach this problem?
no clue
Well, what shapes do you see?
semicircle and rectangle
rectangle is 24
Hmm, if you do a rectangle, you leave a semicircle on the bottom. Then you have two semicircles that you have to solve for.
yeah, i dont know how to do the semicirlces though
Do you know how to solve for the area of a circle?
a= 3.14 r^2
\[A = \pi r^2\] Correct. So what do we need in order to solve that?
radius?
What is the radius half of?
diameter
What is the diameter?
Of any circle
Define it for me
the width
A straight line through the center that goes from one point on the edge of a circle, to the other edge?
somebody actually just gave me the answer so im done with this one XD
What did they get?
12+9.125
Do you know how they got that?
kinda
Well, since in the picture it gives us two points on the semicircle ... |dw:1519344134200:dw| We can draw the diameter. That also gives us a triangle. We know how to solve triangles, just (3 times 8)/2 which is 12. You could actually solve this correctly using Pythagoras' Theorem to get the hypotenuse (since it's a right angle) then halving what you get for the radius of the semi circle. Then you'd use A = pir^2 then divide it by 2 to get the area of the semi circle.
okay
Hypotenuse is approx 8.5, half it for radius. 4.25 Square it for A = pi r^2, you get approx 18, half it, you get approx 9
Thus \[12 + 9.125\pi\]
okay i understand now.
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