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Mathematics 20 Online
hardlyhuman:

@Shadow

hardlyhuman:

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Shadow:

How do you think we should approach this problem?

hardlyhuman:

no clue

Shadow:

Well, what shapes do you see?

hardlyhuman:

semicircle and rectangle

hardlyhuman:

rectangle is 24

Shadow:

Hmm, if you do a rectangle, you leave a semicircle on the bottom. Then you have two semicircles that you have to solve for.

hardlyhuman:

yeah, i dont know how to do the semicirlces though

Shadow:

Do you know how to solve for the area of a circle?

hardlyhuman:

a= 3.14 r^2

Shadow:

\[A = \pi r^2\] Correct. So what do we need in order to solve that?

hardlyhuman:

radius?

Shadow:

What is the radius half of?

hardlyhuman:

diameter

Shadow:

What is the diameter?

Shadow:

Of any circle

Shadow:

Define it for me

hardlyhuman:

the width

Shadow:

A straight line through the center that goes from one point on the edge of a circle, to the other edge?

hardlyhuman:

somebody actually just gave me the answer so im done with this one XD

Shadow:

What did they get?

hardlyhuman:

12+9.125

Shadow:

Do you know how they got that?

hardlyhuman:

kinda

Shadow:

Well, since in the picture it gives us two points on the semicircle ... |dw:1519344134200:dw| We can draw the diameter. That also gives us a triangle. We know how to solve triangles, just (3 times 8)/2 which is 12. You could actually solve this correctly using Pythagoras' Theorem to get the hypotenuse (since it's a right angle) then halving what you get for the radius of the semi circle. Then you'd use A = pir^2 then divide it by 2 to get the area of the semi circle.

hardlyhuman:

okay

Shadow:

Hypotenuse is approx 8.5, half it for radius. 4.25 Square it for A = pi r^2, you get approx 18, half it, you get approx 9

Shadow:

Thus \[12 + 9.125\pi\]

hardlyhuman:

okay i understand now.

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Shadow:

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