I actually need help Jake takes 6 hours to complete a particular job. Suppose he and John begin working on the job together, after 2 hours Jake leaves. If John completes the job himself an hour later, how long would it have taken John to complete the same job if he worked alone?
so what I have so far: Jake by himself = 6 hours Some Combination = (2 hours of J+J) + (1 hour of John by himself) want to find John by himself = ? hours
the johns and jakes make it confusing, why couldn't it be 2 more different names lol
I know right haha how about this A = Jake B = John
D = Rate * time Wouldn't we use this formula
where d represents number of houses and not distance
yeah but I guess it would be a sum like (combined rate)*(time of combined) + (john rate)*(time john took) = 1 whole job
im trying to bring nightowl into this lmaooo
x = rate of jake y = rate of john 1 = x * 6 would be jake 1 = (x + y) * 2 + y * 1 expanded 1= 6x 1 = 2x + 3y solve for x x = 1/6 substitute into the 2nd equation 1 = 2 (1/6) + 3y 1 = 2/6 + 3y 1 - 2/6 = 3y 1 - 1/3 = 3y 2/3 = 3y y = 2/3 * 1/3 y = 2/9 hours
@BlankSpace nightowl's a genius fam lol
I just got to that answer myself.... but that means that John is a freaking demon doing a job that takes Jake 6 hours, he does it in less than 14 minutes
I was doubting myself for a good few minutes but thank nightowl for me
he says he only has an undergraduate math degree lol
John is Barry Allen
this is... from my high school math course i.e. high school math content for future teachers
lol shadow
wait nightowl is telling me otherwise
says 2/9 is the rate at which John completes a single house but to find the time... 1 = 2/9 * t 9/2 hours = t
4.5 hours
that makes more sense x'D
One of these days we will be able to get nightowl aboard the QC ship... x'D
He exists.
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