V = πr2h h = 3xr = 9 V = π(3)2(9) = 81π ≈ 254.34 inches3
where did the x come from it went from pi2h and then 3xr where did the x come from?!
@563blackghost
I'm guessing your solving for the volume of a cylinder cause of the formula, but where exactly did you get this solution? And is there a diagram for this problem?
Okay I see.
If you look in the beginning the question states `"a height that is triple the radius"`. This would indicate that we do not know what the radius is so we have it as a variable `r`. Though the `x` is unusual. It might be indicating 3x `x` being the variable for the radius. @dude what do you think?
ok lol
I agree with ya ghost :3
I mean if the `x` means multiply then it would be represented as a dot.
how did he get 3?
`triple` = `3`. So we are multiplying the radius by `3`.
Okay I understand
awesome >.< is there anything else that you don't understand?
it says Use 3.14 for pi. Does that mean for every question that I do that says that whatever answer i get i have to divide it by pi?
grammar lol
When you are told to `use 3.14 for pi` it simply means to substitute it in there for whatever formula you are using being it an area for a circle, circumference etc.
They state this because sometimes they will make you keep it in terms of `pi`.
Does that mean whatever answer I get I have to divide it by pi?
No. When you plug in pi as `3.14` you have already completed the stated use. The final answer is your final answer.
then why does it go 81pi to 254.34 inches3
That's simply becuase they kept the terms of `pi` then plugged in `pi` as `3.14`. This resorts to them having to multiply it. If you plugged `pi` in the beginning and solved all the way through you would come to the same answer.
so that means when it says use pi all I do is plug in pi
yup
how did they get 4/3 pi27= 36?
Well the formula for volume of a sphere is \(\large\bf{\frac{4}{3} \pi r^{3}}\). They are told the diameter of the sphere is `6`, but to find the radius you divide it by `2` and get `3`. So the `radius = 3`. So they plug that in. \(\large\bf{\frac{4}{3} \pi (3)^{3}}\) So we simplify \(\bf{3^{3}} = 3 \times 3 \times 3 = 9 \times 3 = {\large\bf{\color{red}{27}}}\) So we get \(\large\bf{\frac{4}{3} \pi (27)}\) in which we `multiply 4 by 27` then `divide by 3` to get 36 `we keep pi in terms of pi`. \(\Large\bf{\frac{4 \times 27}{3} \pi (27) \rightarrow \frac{108}{3}\pi \rightarrow \color{red}{36 \pi}}\)
whoops that `pi (27)` is a mis type it is suppose to be just `pi`.
why do we do 9 times 3?
i thought we used up all the threes
lol
It's because of the powers. `REMEMBER THAT HOLDING TO A POWER IS MULTIPLYING ITSELF`. \(\large\bf{3^{3} = 3 \times 3 \times 3}\) We simply start pairing to solve. So we do `3x3` first. \(\large\bf{3 \times 3 = 9}\) \(\large\bf{3 \times 3 \times 3 \rightarrow 9 \times 3}\) We are left with one 3 so we multiply that by 9. \(\large\bf{3 \times 9 \rightarrow \color{red}{27}}\)
yea lol i just got confused cause you did 3x3x3=9
Thank you
No problem! If you have any other questions and I'm free just tag meh ;)
lol ok
Join our real-time social learning platform and learn together with your friends!