help
@Vocaloid
@Vocaloid
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use the second angle identity to find cos(75) by letting theta = 150 degrees
cos 75=.258
we are looking for an exact value so we cannot just plug this into a calculator, you have to go through the formula + calculations.
b?
well done
2?
for #2? I think so, technically identity 1 would work but I think 2 is closer to what they want
as a hint for #3, you can re-write the product and put sin and cos together
is it d
for 2
3 give me a minute
c? c and almost look identical lol
d
good, D, the difference is where the 2 is wrt theta
is 2 d ?
for #2 I'm not 100% sure, C and D seem too far from what the identity needs, I was between A and B sort of leaning towards B? :S
oh ok b it is then you're the genius I try lol
you were right
can you help with more
I'll try
for 1) you just have to know the definitions of the functions, for example tan(theta) is sin/cos not the other way around, so check 1 is not marked off keep going with the other possibilities, eliminating the ones that are not mathematically correct
those are the identities i can probably find it
b is one
good, there's one more, it's pretty easy to find once you look at the csc and sec definitions
csc = 1/sin sec = 1/cos based on this which one(s) can you eliminate?
both because both in answer choices are wrong lol
good so it's just B + the last choice
is sec tan /sin
number 2?
if you re-write tan as sin/cos then sec = (sin/cos)/sin, then the sins cancel out and you get 1/cos which is equal to sec
anyway, for 2: I'm not 100% sure but we could at least eliminate a few choices that aren't helpful, like the first one probably isn't helpful since we're dealing with cot and sec in separate parts of the fraction
my best (?) guess would be to re-write everything in terms of tan, you'd use identifies B and D to do that :S so those two?
I trust your answer so we'll go with it lol
notice how he replaced sec^2 with 1/(sin^2) what do you think is the problem with that?
doesn't cos with sec not sec and sin
b lol
good, so sec^2 isn't 1/sin^2 it's 1/cos^2 making the error in answer choice B, well done
a?
for Albert's proof, C and D are factually incorrect so we immediately eliminate these you're on the right track, but he's already done tan(theta) = sintheta/costheta, he has to do something else to make the left side equal to the right side
if he re-writes that cos as cos^2 / cos then he can also re-write sec as 1/cos, giving them all common denominator cos, so B
6 is a
as a hint, cos^2 = 1 - sin^2 so what would we need to do to make the denominator 1 - sin^2 instead of 1 - sin? think back to algebra, difference of squares
multiply
good but multiply by what?
A^2 - B^2 = (A+B)*(A-B) 1^2 - sin^2 = ____ * (1-sin) fill in the blank
is answer d?
good, you'd multiply by 1 + sin following the rule, so D
6 is a
for 7, use the tan sum identity, treat "alpha" as x1 and "beta" as (x1+x2)
yeah 6 is a that's just a quick calculation check
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b?
check the sign in the numerator, notice how it's positive
c
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see how we plugged in x2 + x3 for beta, and how tan(x2+x3) has to keep x2 and x3 in parentheses?
oh its d okay same set up but different symbol ok
yup good
have to re-write cos(3x) as cos(2x + x) then use the cos sum formula to expand cos(3x)
cos(A+B)=cosAcosB−sinAsinB where A is 2x and B is x, then after that you need to keep expanding until you get something that looks like one of the choices
b
can you show me your calculations? still working on it myself
honestly mathway said that well something close to it it gave me an odd cal
I'll just get back to 8, I can't figure out the calculation yet anyway for 9 you just want to use the half angle formula to calculate sin(theta/2) where theta = 45|dw:1520483832309:dw|
please at least attempt the calculations
a
you're getting there but that's just the sin value, since the force is mg sin theta you must multiply the result from A by m and g (given in the problem so what do you get?)
c
m * g = 0.01 * 9.8 = 0.049/2 combine this with what we got from before
oh ok I think I got it maybe but d is the answer
we got sintheta = sqrt(2 - sqrt(2))/2 multiply this with 0.049 * 2 what do you get?
so the denominator is multiplied ? does that mean the answer is b kinda lost on this topic but am attempting
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anyway, yeah it's B, I finally figured out # 8 so we can get back to that
okay thank you for hwlping I know I'm annoying
anyway, for cos(3x) we can split this into cos(2x + x) using the cos addition formula we get:
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plugging 2x for alpha and x for beta cos(2x)cos(x) - sin(2x)sin(x) all of that goes over cos(x) sin(x) so we write it like:
|dw:1520484864460:dw|
we can split this fraction into two fractions like so:
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we can cancel out common units like so:
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anyway, if you remember our definitions of csc and sec from before, you can re-write these in terms of csc and sec, what would be your final answer?
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does this make it a little more clear to see how it can be re-written in terms of sec and csc?
yes b and c are the only ones written in that form
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substituting csc for 1/sin and sec for 1/cos gives us cos(2x)csc(x) - sin(2x)sec(x) answer choice A
anyway I still gotta think about #10, I know A is nonsense so it's out
last question and then i'll try and figure the other out if not i'll be back
cos^(theta) = [ 1 + cos(2theta) ] /2 if we replace "theta" with "2theta" we get cos^(2theta) = [1 + cos(4theta) ] / 2 making the first answer choice the only one that is mathematically valid
for 10 or 11
11
sorry doing math and art history at the same time if you know an art history genius please let me know lol
anyway, for 10, I am not 100 on this but since we have tan(3theta) not tan(2theta) using the double angle formula would result in a tan(3theta/2) term which gets us "stuck" so C
anyway I hope that helps, sorry if there are any errors it's past midnight and I'm kind of burnt out
I'll ask around for art history
okay thank you and it's okay better than I would've gotten
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