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Mathematics 18 Online
kaylak:

help

kaylak:

@Vocaloid

kaylak:

1 attachment
kaylak:

@Vocaloid

Vocaloid:

|dw:1520479379634:dw|

Vocaloid:

use the second angle identity to find cos(75) by letting theta = 150 degrees

kaylak:

cos 75=.258

Vocaloid:

we are looking for an exact value so we cannot just plug this into a calculator, you have to go through the formula + calculations.

kaylak:

b?

Vocaloid:

well done

kaylak:

2?

Vocaloid:

for #2? I think so, technically identity 1 would work but I think 2 is closer to what they want

Vocaloid:

as a hint for #3, you can re-write the product and put sin and cos together

kaylak:

is it d

kaylak:

for 2

kaylak:

3 give me a minute

kaylak:

c? c and almost look identical lol

kaylak:

d

Vocaloid:

good, D, the difference is where the 2 is wrt theta

kaylak:

is 2 d ?

Vocaloid:

for #2 I'm not 100% sure, C and D seem too far from what the identity needs, I was between A and B sort of leaning towards B? :S

kaylak:

oh ok b it is then you're the genius I try lol

kaylak:

you were right

kaylak:

can you help with more

Vocaloid:

I'll try

kaylak:

1 attachment
Vocaloid:

for 1) you just have to know the definitions of the functions, for example tan(theta) is sin/cos not the other way around, so check 1 is not marked off keep going with the other possibilities, eliminating the ones that are not mathematically correct

kaylak:

those are the identities i can probably find it

kaylak:

b is one

Vocaloid:

good, there's one more, it's pretty easy to find once you look at the csc and sec definitions

Vocaloid:

csc = 1/sin sec = 1/cos based on this which one(s) can you eliminate?

kaylak:

both because both in answer choices are wrong lol

Vocaloid:

good so it's just B + the last choice

kaylak:

is sec tan /sin

kaylak:

number 2?

Vocaloid:

if you re-write tan as sin/cos then sec = (sin/cos)/sin, then the sins cancel out and you get 1/cos which is equal to sec

Vocaloid:

anyway, for 2: I'm not 100% sure but we could at least eliminate a few choices that aren't helpful, like the first one probably isn't helpful since we're dealing with cot and sec in separate parts of the fraction

Vocaloid:

my best (?) guess would be to re-write everything in terms of tan, you'd use identifies B and D to do that :S so those two?

kaylak:

I trust your answer so we'll go with it lol

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Vocaloid:

notice how he replaced sec^2 with 1/(sin^2) what do you think is the problem with that?

kaylak:

doesn't cos with sec not sec and sin

kaylak:

b lol

Vocaloid:

good, so sec^2 isn't 1/sin^2 it's 1/cos^2 making the error in answer choice B, well done

kaylak:

a?

Vocaloid:

for Albert's proof, C and D are factually incorrect so we immediately eliminate these you're on the right track, but he's already done tan(theta) = sintheta/costheta, he has to do something else to make the left side equal to the right side

Vocaloid:

if he re-writes that cos as cos^2 / cos then he can also re-write sec as 1/cos, giving them all common denominator cos, so B

kaylak:

1 attachment
kaylak:

6 is a

Vocaloid:

as a hint, cos^2 = 1 - sin^2 so what would we need to do to make the denominator 1 - sin^2 instead of 1 - sin? think back to algebra, difference of squares

kaylak:

multiply

Vocaloid:

good but multiply by what?

Vocaloid:

A^2 - B^2 = (A+B)*(A-B) 1^2 - sin^2 = ____ * (1-sin) fill in the blank

kaylak:

is answer d?

Vocaloid:

good, you'd multiply by 1 + sin following the rule, so D

kaylak:

6 is a

Vocaloid:

for 7, use the tan sum identity, treat "alpha" as x1 and "beta" as (x1+x2)

Vocaloid:

yeah 6 is a that's just a quick calculation check

Vocaloid:

|dw:1520482611500:dw|

kaylak:

b?

Vocaloid:

check the sign in the numerator, notice how it's positive

kaylak:

c

Vocaloid:

|dw:1520482844699:dw|

Vocaloid:

see how we plugged in x2 + x3 for beta, and how tan(x2+x3) has to keep x2 and x3 in parentheses?

kaylak:

oh its d okay same set up but different symbol ok

Vocaloid:

yup good

kaylak:

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Vocaloid:

have to re-write cos(3x) as cos(2x + x) then use the cos sum formula to expand cos(3x)

Vocaloid:

cos(A+B)=cosAcosB−sinAsinB where A is 2x and B is x, then after that you need to keep expanding until you get something that looks like one of the choices

kaylak:

b

Vocaloid:

can you show me your calculations? still working on it myself

kaylak:

honestly mathway said that well something close to it it gave me an odd cal

Vocaloid:

I'll just get back to 8, I can't figure out the calculation yet anyway for 9 you just want to use the half angle formula to calculate sin(theta/2) where theta = 45|dw:1520483832309:dw|

Vocaloid:

please at least attempt the calculations

kaylak:

a

Vocaloid:

you're getting there but that's just the sin value, since the force is mg sin theta you must multiply the result from A by m and g (given in the problem so what do you get?)

kaylak:

c

Vocaloid:

m * g = 0.01 * 9.8 = 0.049/2 combine this with what we got from before

kaylak:

oh ok I think I got it maybe but d is the answer

Vocaloid:

we got sintheta = sqrt(2 - sqrt(2))/2 multiply this with 0.049 * 2 what do you get?

kaylak:

so the denominator is multiplied ? does that mean the answer is b kinda lost on this topic but am attempting

Vocaloid:

|dw:1520484678600:dw|

Vocaloid:

|dw:1520484709652:dw|

Vocaloid:

anyway, yeah it's B, I finally figured out # 8 so we can get back to that

kaylak:

okay thank you for hwlping I know I'm annoying

Vocaloid:

anyway, for cos(3x) we can split this into cos(2x + x) using the cos addition formula we get:

Vocaloid:

|dw:1520484811165:dw|

Vocaloid:

|dw:1520484819494:dw|

Vocaloid:

plugging 2x for alpha and x for beta cos(2x)cos(x) - sin(2x)sin(x) all of that goes over cos(x) sin(x) so we write it like:

Vocaloid:

|dw:1520484864460:dw|

Vocaloid:

we can split this fraction into two fractions like so:

Vocaloid:

|dw:1520484892827:dw|

Vocaloid:

|dw:1520484928186:dw|

Vocaloid:

we can cancel out common units like so:

Vocaloid:

|dw:1520484976185:dw|

Vocaloid:

anyway, if you remember our definitions of csc and sec from before, you can re-write these in terms of csc and sec, what would be your final answer?

Vocaloid:

|dw:1520485207707:dw|

Vocaloid:

does this make it a little more clear to see how it can be re-written in terms of sec and csc?

kaylak:

yes b and c are the only ones written in that form

Vocaloid:

|dw:1520485377143:dw|

Vocaloid:

substituting csc for 1/sin and sec for 1/cos gives us cos(2x)csc(x) - sin(2x)sec(x) answer choice A

Vocaloid:

anyway I still gotta think about #10, I know A is nonsense so it's out

kaylak:

last question and then i'll try and figure the other out if not i'll be back

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Vocaloid:

cos^(theta) = [ 1 + cos(2theta) ] /2 if we replace "theta" with "2theta" we get cos^(2theta) = [1 + cos(4theta) ] / 2 making the first answer choice the only one that is mathematically valid

kaylak:

for 10 or 11

Vocaloid:

11

kaylak:

sorry doing math and art history at the same time if you know an art history genius please let me know lol

Vocaloid:

anyway, for 10, I am not 100 on this but since we have tan(3theta) not tan(2theta) using the double angle formula would result in a tan(3theta/2) term which gets us "stuck" so C

Vocaloid:

anyway I hope that helps, sorry if there are any errors it's past midnight and I'm kind of burnt out

Vocaloid:

I'll ask around for art history

kaylak:

okay thank you and it's okay better than I would've gotten

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