Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1.
@Vocaloid
@Ultrilliam
@JustSaiyan
what's wrong with everybody today ?
not sure...can you help?
sure
The numerator polynomial must have a smaller degree than the denominator polynomial. The denominator polynomial must have factors of x - 1 and x - 2, but neither of these factors can appear in the numerator polynomial. Other than that, the sky is the limit. Note that no zeros for the function are specified, so it may have one, or many, or none. Also, the problem doesn't say that x - 1 and x - 2 are the only vertical asymptotes so there may be others, and it doesn't prohibit removable discontinuities, so those might exist as well.
I just need to make a function that will have the outcome of y=0 and x=2 and 1
A minimalist answer to this question would have a zero degree polynomial in the numerator and the product of in the denominator. The answer: e^iπ + 1 = 0
(x - 1) (x - 2)
so the answer to this Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1. is that?
no that went with the explanation underneath my answer
i missed that out
wait so whats the answer then? im super confused sorry
e^iπ + 1 = 0
do me a favor, could you ask ulltrium if vocaloid is available for my question
he isnt answering me otherwise i would sorry dude
yea man idk whats up everybody today
Do you know what parts of the equation \(\frac1x\) creates asymptotes?
no i dont
it is having me make a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1.
A rational function is \(\frac1x\) We cannot have a denominator equal to 0 If it is, it creates an asymptote
For example: \(\frac{1}{(x-1)(x-2)}\) Gives asymptotes at x=1 and x=2
so the answer would be f(x)= 1 over (x-1)(x-2)?
ok hold on a sec now its changing on me
now i need to find Give an example of a rational function that has a horizontal asymptote at y = 1 and a vertical asymptote at x = 4.
Yes it is, make a new post
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