Ask your own question, for FREE!
Mathematics 18 Online
SourMunchkin7806:

Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1.

SourMunchkin7806:

@Vocaloid

SourMunchkin7806:

@Ultrilliam

SourMunchkin7806:

@JustSaiyan

mikewwe13:

what's wrong with everybody today ?

SourMunchkin7806:

not sure...can you help?

mikewwe13:

sure

mikewwe13:

The numerator polynomial must have a smaller degree than the denominator polynomial. The denominator polynomial must have factors of x - 1 and x - 2, but neither of these factors can appear in the numerator polynomial. Other than that, the sky is the limit. Note that no zeros for the function are specified, so it may have one, or many, or none. Also, the problem doesn't say that x - 1 and x - 2 are the only vertical asymptotes so there may be others, and it doesn't prohibit removable discontinuities, so those might exist as well.

SourMunchkin7806:

I just need to make a function that will have the outcome of y=0 and x=2 and 1

mikewwe13:

A minimalist answer to this question would have a zero degree polynomial in the numerator and the product of in the denominator. The answer: e^iπ + 1 = 0

mikewwe13:

(x - 1) (x - 2)

SourMunchkin7806:

so the answer to this Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1. is that?

mikewwe13:

no that went with the explanation underneath my answer

mikewwe13:

i missed that out

SourMunchkin7806:

wait so whats the answer then? im super confused sorry

mikewwe13:

e^iπ + 1 = 0

mikewwe13:

do me a favor, could you ask ulltrium if vocaloid is available for my question

SourMunchkin7806:

he isnt answering me otherwise i would sorry dude

mikewwe13:

yea man idk whats up everybody today

dude:

Do you know what parts of the equation \(\frac1x\) creates asymptotes?

SourMunchkin7806:

no i dont

SourMunchkin7806:

it is having me make a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at x = 2 and x = 1.

dude:

A rational function is \(\frac1x\) We cannot have a denominator equal to 0 If it is, it creates an asymptote

dude:

For example: \(\frac{1}{(x-1)(x-2)}\) Gives asymptotes at x=1 and x=2

SourMunchkin7806:

so the answer would be f(x)= 1 over (x-1)(x-2)?

SourMunchkin7806:

ok hold on a sec now its changing on me

SourMunchkin7806:

now i need to find Give an example of a rational function that has a horizontal asymptote at y = 1 and a vertical asymptote at x = 4.

dude:

Yes it is, make a new post

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!