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@Vocaloid @563blackghost
is this correct?
You equation is setup correctly but your product is incorrect.
Oh is it. 603.19
If you keep it in terms of pi then yes. Are suppose to keep it as \(\bf{\pi}\) or as 3.14?
Keep it as is
Also make sure your answer ends as: \(\large\bf{V=603.19 ~ cm^{2}}\) otherwise you might get it wrong.
Ohh ok
really crucial to have your units defined otherwise you might get your entire problem wrong even if your calculations are correct.
Yes that actually happened before lol
For the next one you need to know your formula for a volume of a prism: \(\large\bf{V=lwh}\) You know `h=10` and `w=5` and well as the volume wanting to be `200`. So we plug in our info. \(\large\bf{200=l(10)(5)}\) Now we simplify to find `l`. \(\bf{200=l(50)}\) \(\bf{\frac{200}{50} = l}\) What is `l`?
l is 4
yup
First find the volume of the given dimensions. Then you want to try doubling one dimesions each time. \(\large\bf{8×9×16 ~~~~, ~~~ 4×18×16 ~~~~ ,~~~ 4×9×32}\) After that try and divide the doubled dimension by the original. What do you see occurring?
So the volume is 576
Now, do I multiply all the pairs you put?
try each out, yes.
When I multiplied each one, they all ended up with 1152 as the product.
Yes that is correct. Now try and divide the outcome by 576. What is it increasing by?
the answer for that is 2
So this tells you if you increase one dimension the volume will double as well.
Ohh ok...you really smart LOL
>.< well thank you, but i still got much to learn though ;)
I know the formula is: V=a^2*h/3
To find the volume of a square pyramid you need to use the formula: \(\bf{V=a^{2} \frac{h}{3}}\) The `height is 455.4` and the `base (a) is 755.9` Plug this in. \(\large\bf{V=755.9^{2} \frac{455.4}{3}}\)
Ok so first divide the fraction
yea
151.8 and multiply that by 755.92^2
yes
Did you plug this in a calculator?
Cause my outcome was different. I got \(\bf{86736214.16}\)
I used mathway
If you round your answer, it will become my answer
Does that make sense LOL
@563blackghost
hrmmmm did you round the terms before the simplification?
no I just multiplied...I guess its automatic.
oh okie... well i plugged in the equation into my calculator then double checked with mathway but the outcome is the same for meh....
So should I use your answer or my answer or both?
hrmmmm it would be best for a second opinion to see if they get the same outcome.
Ok I can do that later....Can we move on tho?
sure
Do you know your surface area equation for a prism?
umm...noo
The equation is: \(\bf{A=2(wl+hl+hw)}\) First you would find the surface area of the given dimensions then try with one dimension being doubled. \(\bf{2(4(6) + g(6) + 6(4))~~~,~~~2(8(3)+6(3)+6(8)~~~,~~~2(3(4)+12(3)+12(4)}\) What do you see occurring?
Ok so first, A=(4*3+6*3+6*4)
make sure to include the 2.
oh ok
108
yea that is right
I cant see all the pairs...Can you write it again please?
\(\bf{2(4(6) + 6(6) + 6(4))}\) \(\bf{2(8(3)+6(3)+6(8))}\) \(\bf{2(3(4)+12(3)+12(4))}\)
Thats my answers
What do I do now?
So now you would compare if the original surface area really is doubled if one of the dimensions is doubled. Your original surface area is `108`. `108 x 2 = 216` Do any of the pairs equal to 216?
No none of them
So they cannot be doubled?
Correct they aren't. So yes, if the doubling of one dimension occurs the surface area does not double.
@563blackghost
Use this formula for surface area: \(\large\bf{A=2 \pi rh + 2 \pi r^{2}}\) Plug in your given info. \(\large\bf{A=2(3.14)6(11.5)+2(3.14)(6^{2})}\)
The answer is 659.4
Correct?
yea that is right
@563blackghost
@563blackghost
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