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Mathematics 6 Online
vaporeon246:

Sorry to bother but i need help

vaporeon246:

A rectangular pyramid has a base area of \[\frac{ x^2 +3x-10}{ 2x }\] square centimeters and a height of \[\frac{ x^2 -3x}{ x^2 -5x+6} \] centimeters. Write a rational expression to describe thw volume of the rectangular pyramid

Vocaloid:

volume = base * height so you would multiply the two equations now, the hard part is to factor do you know how you would factor x^2 + 3x - 10?

Vocaloid:

*actually it's (1/3)base*height sorry

vaporeon246:

how am i supposed to factor x^2 +3x -10?

Vocaloid:

first you would pick two integers that: add up to 3 and multiply to get -10 can you think of two integers that satisfy these requirements?

vaporeon246:

-5 and 2 or is it 5 and -2?

Vocaloid:

the sum has to be 3, so which pair would it be?

vaporeon246:

5 -2

Vocaloid:

good, so we take the positive 5, negative 2, and write our factors as (x+5)(x-2) now, we keep going for x^2 - 3x, do you see any common factors you can factor out?

vaporeon246:

x

Vocaloid:

good, so we factor that to get x(x-3) now, the last thing, we can factor x^2 - 5x + 6, using the same method from before, pick two numbers that multiply to 6 and add up to -5

vaporeon246:

1 and -6

Vocaloid:

that's a good try but not quite, 1 * (-6) = -6 not positive 6 as a hint both the numbers need to be negative

vaporeon246:

oh ok thanks @Vocaloid

Vocaloid:

so you should get -2 and -3, thus we can re-write x^2 - 5x + 6 as (x-2)(x-3) then we go back to the expression volume = (1/3)bh, now we substitute our factored forms, then cross out what we can:

Vocaloid:

|dw:1521159473444:dw|

Vocaloid:

see anything you can cross out from the num or denominator?

vaporeon246:

x-2

Vocaloid:

good, but there's two more things you can cross out

vaporeon246:

x-3

Vocaloid:

good, one more, it's a little harder to see

vaporeon246:

x?

Vocaloid:

good, so let's start crossing them out

Vocaloid:

|dw:1521159614277:dw|

Vocaloid:

only (x+5)/6 is left so that's your solution

vaporeon246:

ok thank you @Vocaloid

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