A toy rocket launched straight up from the ground with an initial velocity of 80ft/s returns to the ground after 5 s. The height of the rocket t seconds after launch is modeled by the function f(t) = -16t^2+80t What is the maximum height of the rocket, in feet? Explain how you found your answer.
Maximum height is also known as...?
Do you know? @Aureo
Maximum height would be the highest y value
Yes, which is known as what in a parabola?
Ahm. The vertex?
Yes, and how do we calculate the vertex?
Or more specifically, the x-value for the vertex.
To calculate vertex you do \[x=\frac{ -b }{ 2a }\]
Yes, so do it. \(\sf ax^2+bx+c\)
So in this case what is 'b' and what is 'a'?
A would be -16 and b would be 80
Yes, so plug them into the formula to find the x-value of the vertex.
Alright. So it would be -80/-32. Which = 2.5
Yep, now plug that into the equation to find the y-value, which will be our maximum height.
\(\sf f(t)=-16t^2+80t\) \(\sf f(2.5)=-16(2.5)^2+80(2.5)\) Btw, this 2.5 represents 2.5 seconds for it to reach the maximum height.
Ahhh. Thank you!
So then
The feet would be 1800?
Check again, I got something different.
@Aureo
Ah. I squared the wrong one. It's 100
Yep, max height is 100 ft.
Thank you kind sir
Any time
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