Felix’s Feed Mill sells chicken feed for $8.00 per bag. This price is no longer high enough to create a profit. Felix decides to raise the price. He is considering four different plans. Plan A: Raise the price by $0.10 each week until the price reaches $12.00. Plan B: Raise the price by 10 percent each week until the price reaches $12.00. Plan C: Raise the price by the same amount each week for 8 weeks, so that in the eighth week the price is $12.00. Plan D: Raise the price by $0.25 each week until the price reaches $12.00. Which plan will result in the price of the feed reaching $12.00 fastest?
Do you know where to start off from?
@dude I think he’s gone
old question but will answer so this can be closed comparing plans A and D, obviously raising the price by 0.25 per week will make it reach 12 sooner than raising it by 0.10. eliminate A as a possible answer choice. Then we just have to compare B, C, and D Plan B: Raise the price by 10 percent each week until the price reaches $12.00. we can model this with the equation (final amount) = (initial amount)(1 + 0.10)^t where t is the number of weeks. plugging in the numbers from the problem 12.00 = 8.00(1.1)^t simply solve for t Plan C: Raise the price by the same amount each week for 8 weeks, so that in the eighth week the price is $12.00. this will take 8 weeks, as stated. so for this one t = 8 weeks. Plan D: Raise the price by $0.25 each week until the price reaches $12.00. the price needs to be raised from 8 dollars to 12 dollars. so this is an increase of 4 dollars. divide 4 dollars by (0.25 per week) to get the number of weeks t finally compare which plan out of the three has the smallest t value
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