Question

@vocaloid help

Answer 1

well for 1) there's an x-value where there's a clear jump/gap in the graph, what it is?

Answer 2

*what is it?

Answer 3

-1 you mean a hole

Answer 4

that's what we call them

Answer 5

good

for 2) in order for the function to be continuous, both pieces of the function need to approach the same value at x = n

so you would just plug in n into both pieces of the function and set them equal to each other

2n + 2 = 4n, solve for n

Answer 6

1

Answer 7

good so 1 = your answer

for 3) try factoring the denominator, you'll notice there's a hole/discontinuity

Answer 8

-5 -2

Answer 9

are the holes

Answer 10

good, so there are discontinuities which means the function is not defined everywhere so answer B is the best bet

Answer 11

for 4) easiest to just sketch it/plug it into graphing software to see if there are any discontinuities

Answer 12

4 must be discontinuous

Answer 13

just not sure why according to answer choices I just know it's impossible because x<-1 and x>1 nothing would work

Answer 14

I mean x<=

Answer 15

because of how the function is defined, it's defined at all values, but has different one-sided limits (I don't remember how that's classified but it's either C or D hold on ;_;)

Answer 16

I thought maybe d but you know this better than I do

Answer 17

yeah I'm thinking more towards D, it's been a while since i've done this though

Answer 18

this is just a look ahead for cal lesson in precal lol

Answer 19

yay 100%