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Mathematics 8 Online
AnimeGhoul8863:

The second part of the new roller coaster is a parabola. 4. Create a unique parabola in the pattern f(x) = ax2 + bx + c. Describe the direction of the parabola and determine the y-intercept and zeros. 5. The safety inspector notes that you also need to plan for a vertical ladder through the center of the coaster's parabolic shape for access to the coaster to perform safety repairs. Find the vertex and the equation for the axis of symmetry of your parabola, and show your work. 6. Create a graph of the polynomial function you created in Question 4.

AnimeGhoul8863:

@BenLindquist @Ultrilliam last one

Ultrilliam:

@dude

AnimeGhoul8863:

it goes with the graph from the first question

AnimeGhoul8863:

\[g(x) = x^3 − 3x^2 − 4x + 12\]

dude:

You are using a \(x^3\)? or it was given?

AnimeGhoul8863:

the whole equation was given to me if thats what u mean

dude:

Ah okay, to find the zeroes look at where the graph crosses the x-axis

AnimeGhoul8863:

is that x-axis right here in the middle of 0-5

dude:

ebjyYDQPSnGOGp0bbcrvow.png

dude:

What are the values of those points?

AnimeGhoul8863:

(2,0) (3,0)

dude:

Right so those are your zeroes, do you know the y-intercept?

AnimeGhoul8863:

2 lines above 10?

dude:

Yes, so what would that point be?

AnimeGhoul8863:

(12,0)

dude:

Almost, make sure they are in the right order \((x,y)\)

AnimeGhoul8863:

(0,12)

dude:

Right

AnimeGhoul8863:

ok so this is the answer tooo?? which question 4?

dude:

Ah this is for 4, also we have to describe the description for the graph. Does it curve up or down? At which parts?

AnimeGhoul8863:

so the answer for question 4 is Zeros: (2,0) (3,0) Y-intercept: (0,12)

AnimeGhoul8863:

it curves down at the x-axis and curves up and the y-axis

AnimeGhoul8863:

^this correct^

AnimeGhoul8863:

so question 5 5. The safety inspector notes that you also need to plan for a vertical ladder through the center of the coaster's parabolic shape for access to the coaster to perform safety repairs. Find the vertex and the equation for the axis of symmetry of your parabola, and show your work.

dude:

not quite for the last part, list a set of points where it goes up, for example When \(∞\le x<2\) it curves down

AnimeGhoul8863:

what that was just gibberish to me

AnimeGhoul8863:

@Ultrilliam

AnimeGhoul8863:

@Ultrilliam

BenLindquist:

uh sorry I can't do this but I can do reports for ya x'D

EndersWorld:

infinity is less than or equal to x is less than or equal to 2

AnimeGhoul8863:

huh??????

EndersWorld:

Exactly

AnimeGhoul8863:

if ur not gonna help please go enders

dude:

So what I wrote was when x is infinity up until x gets to 2, the graph curves down

AnimeGhoul8863:

^so that would be the answer for #4

dude:

Well part of it, we still have to talk about where it curves up

AnimeGhoul8863:

dude i have less than 10 mins can we speed it up a little

AnimeGhoul8863:

dont mean to be rude or anything i just and on a time limit and need it done

dude:

When x equals negative infinity to when x equals 2 the graph curves down, when x is 2 until x is positive infinity it curves up

AnimeGhoul8863:

ok so that plus the markers would be the answer for #4

dude:

Yes

dude:

Alright this is a cubic function which just makes this process a bit longer for #5 Do you know the vertices of the graph?

AnimeGhoul8863:

No thats why im here

dude:

So its the part where the graph is at its highest or lowest in the curve

dude:

_2ux36NPRki0XiQhPDHc7A.png

AnimeGhoul8863:

ok

AnimeGhoul8863:

@dude Where did u go?

AnimeGhoul8863:

@MissSugarPink132

AnimeGhoul8863:

@bananas

bananas:

Dude too long didn't read, can you post a new thread with unanswered bits

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