Question

What is the Celsius temperature of 1 mole of a gas that has an average kinetic energy of 4,290 joules?

Answer 1

Hi and welcome to QuestionCove!
The relevant equation for this problem is K = (3/2) * (R/N) * T,
where K is the average Kinetic energy of the gas, R and N are constants, 8.314 Joules/mole*Kelvin and Avogadro's number, respectively, and T is Temperature.
If you simplify the constants, you'd get K = 2.071 * (10^(-23)) * T.
Now, if you plug in 4290 Joules for K and solve for T, you'll get the temperature in Kelvin. To get the temperature in Celcius, just subtract 273 from that.
It's a pretty big number, but don't be overwhelmed!