Question

4. Create a unique parabola in the pattern f(x) = ax2 + bx + c. Describe the direction of the parabola and determine the y-intercept and zeros.

Answer 1

My equation o G(x)=x3−3x2−4x+12

Answer 2

@Ultrilliam

Answer 3

@BenLindquist

Answer 4

@Shadow

Answer 5

@Shadow

Answer 6

Did you make the equation?

Parabola format is \(\bf{ax^{2}+bx+c}\) you started with \(\bf{x^{3}}\) this makes the equation into a cube format.

How about setting it at just \(\bf{-3x^{2}-4x+12}\)?

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863
My equation o G(x)=x3−3x2−4x+12
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 8

so if we took ^^^ and did it as f(x)=-3x^2-4x+12

Answer 9

that would be the parabola

Answer 10

yes

Answer 11

now you can find the zeroes.

Answer 12

To find it it's best to use the quadratic formula.

\(\Large\bf{x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}}\)

Just plug in the equation.

`a = -3`
`b = -4`
`c=12`

So you would have to solve for 2.

\(\Large\bf{x=\frac{-(-4) + \sqrt{(-4)^{2}-4(-3)(12)}}{2(-3)}}\)

\(\Large\bf{x=\frac{-(-4) - \sqrt{(-4)^{2}-4(-3)(12)}}{2(-3)}}\)

This will give you your zeroes.

Answer 13

im sooooooo confused what are the zeros

Answer 14

@563blackghost

Answer 15

If you don't know on how to find the zeroes, then I can not help you since the equation is asking for info you have not learned. @AnimeGhoul8863

Here is a site that can help find the zeroes.
http://www.biology.arizona.edu/biomath/tutorials/quadratic/roots.html

Answer 16

@563blackghost im not saying i cant find the zeros im saying im a little confused on ur equations but ok

Answer 17

What are you exactly confused on?

There are 2 ways you can find the roots, squaring the function or using the quadratic formula. I simply used the quadratic formula.

Answer 18

i guess im confused bc im not good at fractions or formula's