Question

Quadratic rate of change

Answer 1

@Hero

Answer 2

I know the steps it's just the fraction that messes me up

Answer 3

Rate of change formula for a quadratic function:
\(\overline{\triangle} = \dfrac{f(b) - f(a)}{b - a}\), where a and b are any two values of \(x\) on the graphh of \(f(x)\)

Answer 4

I know how to do this it's the fraction that messes me up

Answer 5

Pretty straight forward to me. What's supposedly confusing you about it?

Answer 6

-3 + 2 = 1^2 1
-1/2 x 1 = -1/2

Answer 7

Im just bad at fractions in general

Answer 8

-1/2 + 5 = 4 1/2

Answer 9

right?

Answer 10

Why don't you try using the equation button to post your fraction?

Answer 11

too lazy

Answer 12

Are you going to help me?

Answer 13

Use the drawing feature to post your answer. I need something better than what you posted above. It looks a little incoherent as currently presented.

Answer 14

5.5 = -3
-2 = 1

Answer 15

What I mean is, show your work by applying the formula above.

Answer 16

How about start with:
\(\dfrac{f(1) - f(-3))}{1 -(-3)}\)

Answer 17

my teachers say differently

Answer 18

to get the x,y values then do the formula

Answer 19

\(=\dfrac{-\dfrac{1}{2}(1 + 2)^2 + 5-(-\dfrac{1}{2}(-3 + 2)^2 + 5)}{1-(-3)}\)
\(=\dfrac{1.5 -(2.5)}{1-(-3)}\)
\(=-\dfrac{1}{4}\)

Answer 20

i got -1 with a rate of change calculator

Answer 21

How do we know you entered the information correctly?

Answer 22

\(=\dfrac{-\dfrac{1}{2}(1 + 2)^2 + 5-(-\dfrac{1}{2}(-3 + 2)^2 + 5)}{1-(-3)}\)
\(=\dfrac{0.5 -(-2.5)}{1-(-3)}\)
\(=\dfrac{3}{2}\)

Answer 23

That's my next calculation. If that isn't it, then oh well. The important thing is understanding the method.

Answer 24

i got it right

Answer 25

Next time I get a problem like this, I'm just going to do it on paper first rather than trying to type it all up and do ALL of the math mentally.

Answer 26

Yep, it's -1. Did the math mentally. I see exactly where I messed up.