Question

Doing meth with Hero

Answer 1

meth ruins lives...Dont Do Drugs Kids

Answer 2

The expression \[20x^2-36xy+16y^2\] is equivalent to

\[(5x+8y)(4x+8y)\]
\[(5x-8y)(4x+2y)\]
\[(2x+y)(10x-16y)\]
\[4(x-y)(5x-4y)\]
\[(20x+8y)(x-2y)\]

Answer 3

By meth, he means math. He's implying that after attempting to understand math, his brain state is the same as if he tried meth, which I assume he has not. Meth is just a spin-off of math which is supposedly mental abuse to humans, but it's not really true. But judging by the number of people here, you all must really be curious about meth. Please don't experiment with drugs. If you came here looking for drugs, sorry to disappoint you.

Answer 4

Thanks @hero 😂 😂

Answer 5

@EndersWorld so how far did you get with your factorization attempt? Post the steps according to the method I showed you.

Answer 6

No where.

Answer 7

I tried, lemme go back LOL

Answer 8

You can at least attempt the first step.

Answer 9

Yes, go back and read the tutorials I posted on this.

Answer 10

And that’s to find the two products that equal B when added and AC when multiplied?

Answer 11

Two numbers*

Answer 12

But do you remember the process for actually finding those two numbers?

Answer 13

Sorry, yea. So B is -36 and AC is 320

Answer 14

Okay, so what would you do first?

Answer 15

Kinda sorta... sorry, I’m going through a lot in my personal life..

Answer 16

Find the products of 36

Answer 17

Actually, you start with 320 and find two numbered factors for it starting with (1)(320)

Answer 18

I need the products of 320?

Answer 19

Yes, correct, you're finding two-numbered factors for 320 one step at a time.
(1)(320)
(2)(160)

Are the first two factorizations.

Answer 20

You keep listing paired factors until you get to one where their sum is 36.

Answer 21

(4)(80)

Answer 22

Great. Keep going

Answer 23

(5)(64)

Answer 24

(8)(40)

Answer 25

Bam^

Answer 26

What's 40 - 8?

Answer 27

Crap... I’m misread LOL

Answer 28

(20)(16)

Answer 29

Correct

Answer 30

Now what do we do? If you're stuck on what to do next, refer to the tutorials.

Answer 31

-20+-16=-36
-20*-26=320

Answer 32

Excellent! So, now what?

Answer 33

Weee... uh.... plug it in?

Answer 34

@EndersWorld do you think you could type the expression you're referring to here with the "plugged-in" values? Go ahead and give it a shot. You're doing very well atm.

Answer 35

That’s where I am stuck.

Answer 36

Can you at least retype the original expression here?

Answer 37

\[20x^2-36xy+16y^2\]

I want to say \[20x^2-(-20+-16)+16y^2\]

Answer 38

Except if you did that, you'd be making the same mistake I made yesterday. It's best to just replace the 36 with 20 + 16 don't forget the xy outside the parentheses though.

Answer 39

So leave off the negatives?

Answer 40

Correct. Go ahead and re-post your expression knowing this.

Answer 41

\[20x^2(20+16)xy+16y^2\]

Answer 42

More like
\(20x^2 - (20 + 16)xy + 16y^2\)

We're not changing the expression, we're just simply replacing 36 with 20 + 16

Answer 43

But now, the next step will be to use the distributive property to distribute the negative and the xy to both the 20 and the 16.

Answer 44

\[20x^2-20xy-16xy+16y^2\]

Answer 45

Excelente! Now what?

Answer 46

stares at you blankly with a dead look in my eyes

Answer 47

I see. So the next step is to "Factor By Grouping". Factor the first 2 terms. Then factor the last two terms. Go ahead and give it a try.

Answer 48

Wasn’t there a formula to that?

Answer 49

Ah, I see, you may not yet know how to factor. What you do is look for what is common to the first two terms. Then extract them out. The formula to use for this is the distributive property in reverse.

Answer 50

4x for \[20x^2-20xy\]

Answer 51

Or \[20x\]... I’m lost

Answer 52

20x is correct. 20 is clearly common to both. Don't worry, I suspect you know the correct answer. We will get there in the end. So knowing that, go ahead and post the correct factorization for both sets so far.

Answer 53

We're doing this ONE step at a time.

Answer 54

And I suck at it..

Answer 55

That's good except that when you factor out those terms. What remains in the parentheses should MATCH. In order for them to match, you must remember to factor out -1 from the second factorization so actually, you should have

\(20x(x - y) - 16y(x - y)\)

Answer 56

But you did great with that attempt. That was far better than what I predicted you would do. So now, remember that what remains is the expression in parentheses that is common to both factorizations So we now have to factor that out as well. Any ideas?

Answer 57

I’m looking for a factor IN the parentheses?

Answer 58

What's in the parentheses IS the factor that needs to be factored out.

Answer 59

Notice that what needs to be factored out is a binomial and what remains will also be a binomial.

Answer 60

I feel dumb... ಠ_ಠ like for real..

Answer 61

Would I take 4 out of the \[20x\] and \[-16y\]

Answer 62

So basically, when you factor out the \((x - y)\) which is common to both factorizations, you end up with \((x - y)(20x - 16y)\) but we're not done yet.

Answer 63

And as you noticed, the reason we are not done is because now, 4 is common to 20 and 16 so we have to factor it out as well.

Answer 64

Any idea what the final expression will be now after factoring out the 4?

Answer 65

It's more like:
\(20x^2 - 36xy - 16y^2\) = \(20x^2 - (20 + 16)xy - 16y^2\)
= \(20x^2 - 20xy - 16xy - 16y^2\)
= \(20x(x - y) - 16y(x - y)\)
= \((x - y)(20x - 16y)\)
= \(4(x - y)(5x - 4y)\)

Answer 66

The step right before the end is very important to understand. The steps cannot be skipped.

Answer 67

I didn’t wrote down every step, sorry XD. My mind is scrambled.

Answer 68

Not to worry, every student struggles with this at first. Trust me. For me, though, math was always like puzzles and games.

Answer 69

Gonna make me a sandwich, then will you be ready to tackle the next one? Hopefully it will go smoother.

Answer 70

The next one is a fraction 0_0

Answer 71

Oh boy. I know you'll be ready for it though :D

Answer 72

Hold me Hero, I’m scared 😂

Answer 73

Not to worry, the world will not be ending tonight.

Answer 74

Food 🤤

Answer 75

Ugh, people still eat that? Wow

Answer 76

What? Sandwiches?

Answer 77

I mean, I can just tell the quality of the bread is very poor amongst other things. Nothing looks organic or anything. I'm mostly vegan anyway.

Answer 78

I live in South Carolina, nothing is exactly “good quality” and to be honest, I threw it together so I could eat fast and hopefully do one more problem

Answer 79

I have leuttece on it

Answer 80

I did have a glass of fat free milk earlier, and some yams.

Answer 81

Yeah, you have lettuce on it but lettuce is really low on the nutritional vegetable scale. Spinach is far better to use. Also, Vegan-aise would be a better sandwich spread and Rudi's Sprouted Spelt bread would be ideal. Also, you can use avocado in place of meat and Follow Your Heart for Vegan Cheese. Trust me, it would be the best sandwich ever, especially with a sliced tomato and a bit of Sriracha sauce.

Answer 82

Shhhh, you are making me hungry... and I just ate..

Answer 83

Also, I realize we could have done what we did as a first step with \(2x^2 - 6x - 8\) with \(20x^2 - 36xy - 16y^2\) as well because 4 is common here.

Answer 84

I see.

Answer 85

There's more than one way to factor, but usually what you do is look at all three terms and see if there is anything common first. That is the REAL first step.