Question

Help me ;~;

Answer 1

\[\frac{ 2x^2-6x-8 }{ x^2-1 }\]

Answer 2

I’m really confused.

Answer 3

Ah I see. So with these, you factor one at a time. Let's start with \(2x^2 - 6x - 8\)

Answer 4

With this one, you have to look to see what is common to each factor first and then factor that out. Do you see?

Answer 5

ac I have set a \[-4\] BTW

Answer 6

What we're trying to do is figure out what factor is common to the 2, 6, and 8. Only one number is common to each.

Answer 7

2

Answer 8

Very good, so you'll have to factor that out first.

Answer 9

I divided instead of subtracting.. I’m a idiot e.e

Answer 10

a=1
b=-4
c=-6
ac=-6

Answer 11

Well .... actually, when you factor out a number you do DIVIDE.

Answer 12

...

Answer 13

You divide the coefficient of each term by 2

Answer 14

a=1
b=-3
c=-4
ac=-4

Answer 15

Here's how to write it when you have factored out the 2:
\(2(x^2 - 3x - 4)\) But what you have written above is correct. We still now need to factor \(x^2 - 3x - 4\)

Answer 16

Check chat..

Answer 17

I know my numbers are -4 and 1

-4+1=-3
-4*1=-4

Answer 18

Very good.

Answer 19

\[x^2-(4+1)-4\]

Answer 20

don't forget the x after the parentheses

Answer 21

Ima kill myself *^*
\[x^2-(4+1)x-4\]

Answer 22

Very good. So you know what to do next :D

Answer 23

Distribution. :0

Answer 24

\[x^2+4x-1x-4\]

Answer 25

Very good. Now there are two ways to proceed from here. You could go ahead and factor by grouping which is what I would rather you do at this point. Go ahead and try.

Answer 26

x(4)-(x+4)

Answer 27

Remember, if you have factored correctly, what remains in parenthesis are two binomials that will be the same expression.

Answer 28

x(4)- x(4)

Answer 29

Well, just to clarify, what you wrote the first time was almost correct. Now it is way off.

Answer 30

I will be back on tomorrow morning or so, roughly in 12 hours, I gotta do dishes and shower, sorry to cut it short, thank you so much!

Answer 31

Great...

Answer 32

Good luck.

Answer 33

Okay... so I screwed it up.

Answer 34

x(4)-(x+4)

Answer 35

But that's the same thing you wrote 9 replies ago.

Answer 36

Yep, reposted so I could try and find a different way to make it correct.

Answer 37

Just look back at the previous step before that step and think logically about what you are actually factoring out and what should remain afterwards.

Answer 38

(x+4)(x+4)

Answer 39

Well ... I know. It's a bit confusing for you, but you were supposed to factor out x from the first two terms and factor out -1 from the last two terms doing so, you would have this:
x(x+4) - 1(x + 4)

Answer 40

You’re right, that is very confusing.

Answer 41

Now you should be able to finish from there.

Answer 42

Well, let me do some tricks to help you understand better.

Answer 43

\(\color\red{x}^2+4\color\red{x}\color\green{-}x\color\green{-}4\)

Answer 44

Hopefully you can see red and green to highlight what is common to each pair of binomial terms