Flamo:
Find the distance between the points (-3, 11) and (5, 5).
Flamo:
This one might be easier
Flamo:
\[d = \sqrt({5-11})^2 + (5 - (-3) ) ^2\]
Flamo:
...
Angle:
that's perfect!
Flamo:
Phew!
Flamo:
\[d = \sqrt({-6})^2 + (8)^2 \]
Flamo:
Right?
Angle:
mhm
Flamo:
\[d = \sqrt{-36} + 64 \]
Flamo:
Right?
Angle:
(-6)^2 = (-6)*(-6) = positive 36
Flamo:
Woops.
Flamo:
\[d = \sqrt{36} + 64\]
Angle:
yup
Flamo:
sqrt of 36 = 6, so \[d = 6 + 64\]
Flamo:
Right?
Angle:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Flamo \[d = \sqrt({5-11})^2 + (5 - (-3) ) ^2\] \(\color{#0cbb34}{\text{End of Quote}}\) I was thinking the square root extends over the whole thing? \[d = \sqrt{(5-11)^2 + (5 - (-3) ) ^2}\]
Flamo:
Yeah it does, it just didn't let me do it. Let me fix this.
Flamo:
\[d = \sqrt{36} + \sqrt{64}\]
Flamo:
Something like this.
Flamo:
\[d = 6 + 8 = 14\]
Flamo:
\[d = \sqrt{14}\]
Angle:
\(d = \sqrt{36 + 64}\) I think is different
Flamo:
\[d = 2\sqrt{7}\]
Flamo:
Right?
Flamo:
o, it didn't let me do that for some reason Angle.
Flamo:
Oh, its because I spaced, woops, xD
Angle:
yeah, but try it again but with it all under the square root
Angle:
not separate
Flamo:
Anyways, \[d = 2\sqrt{7}\] is right? right?
Flamo:
Okay I will.
Angle:
no, I don't think 2 sqrt(7) is right
Flamo:
\[d = \sqrt{36+64}\]
Flamo:
o
Flamo:
The answer Choices are 10, \[2\sqrt{10}\], and \[2\sqrt{7}\]
Flamo:
But \[2\sqrt{7} \] makes more sense.
Angle:
but try solving for \[d = \sqrt{36+64}\]
Flamo:
o, Okay.
Flamo:
\[d = \sqrt{36 + 64}\]
Flamo:
\[d = 6 + 8? \]
Flamo:
Or
Angle:
Sauce 36+64 in the square root first
Flamo:
\[d = \sqrt{6 + 8}\]
Flamo:
O
Angle:
*add the 36+64 first
Flamo:
I see
Flamo:
\[d = \sqrt{100}\]
Flamo:
\[\sqrt{100} = 10\]
Flamo:
XD
Angle:
tah dahhh
Flamo:
Ye! Ty!
Flamo:
Hopefully I'm not taking ur time...
Angle:
it's ok I didn't wanna do my own homework anyways :P haha
Flamo:
XD Ty!
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