A pool ball hits a second pool ball with equal mass. The first pool ball comes to a complete stop, while the second pool ball rolls away. How does the velocity of the second pool ball compare to the original velocity of the first pool ball?
A. The second pool ball's velocity will be less than the first pool ball's.
B. The second pool ball's velocity will be the same as the first pool ball's.
C. The second pool ball's velocity will be greater than the first pool ball's.
D. The second pool ball's velocity will be exactly double the first pool ball's.

Question

Bearclaws72 · Answer

Yo I dont know much about Chemistry sorry bruv but found this on the internet

Bearclaws72 · Answer

The collision is approximately elastic. In an elastic collision, kinetic energy is conserved. Also, momentum is conserved. So you have two equations (momentum before = momentum after; kintetic energy before = kinetic energy after), and two unknowns (final speed of first ball and final speed of the second ball). It’s just a basic system of equations. The only solution is that the final speed of the first ball equals the initial speed of the second ball and vice versa.

Bearclaws72 · Answer

Hopefully it helps but if it doesnt than here is the full link https://www.quora.com/When-a-pool-ball-hits-another-ball-at-rest-why-does-the-original-pool-ball-stop-entirely-while-the-other-ball-launches-with-the-first-balls-speed