Math
@Hero
@563blackghost
@Angle
so here we should try to do something called: "Completing the square"
I'll give an example say, we want to complete the square for f(x) = x^2 + 4x + 5 we try to think of a similar/easier version of that equation like, say, (x+2)^2 = (x+2)(x+2) = x^2 + 4x + 4 > see how the only difference is the last number?
there is a difference?
\(x^2 + 4x + 5\) versus \(x^2 + 4x + 4\)
oh
so while we can say that \(x^2 + 4x + 4 = (x+2)(x+2)\) it doesn't really work the same for \(x^2 + 4x + 5\)
can you do an example that is similar to my question because im not following
ok, so the main point I was trying to say is that \(x^2 + 4x + 5 = x^2 + 4x + (4 + 1) = (x^2 + 4x + 4) + 1 = (x+2)(x+2) + 1\)
._.
can you do my question but i do the work
hmm sure, sorry for the confusion x'D I was trying a different approach so for your question: first try solving: (x+6)^2 = ?
2x+36
\((x + 6)^2 = (x+6)(x+6) = ?\)
36x?
WAIT its (x+6)^2
right?
can you try expanding it?
(x+6)(x+6)
good and you can expand it further
x^2+12x
/*
close! I think it's missing something
+26
?
(x+6)(x+6) = (x)*(x) + (x)*(6) + (6)*(x) + (6)*(6) you got = x^2 + 12x + _(6*6)_ ?
.-.
OH
yeah 6 times 6 = 36 not 26
+36
wonderful! so (x+6)^2 = x^2 + 12x + 36 now, how is this different from your question?
+36 ~= +26
^not equal sign fail
exactly! you see it, that's great :) so the idea is that we can add and subtract numbers at the same time and not change anything like 13 + 10 - 10 is still 13 with this idea \(x^2 + 12x + 26 + 10 - 10\) still equals the original question right?
Yes
then we can add parts of it but not others like this: \((x^2 + 12x + 36) - 10\) I added the 26 + 10 parts together, see?
yuh
then we said before that (x+6)^2 = x^2 + 12x + 36 right?
yes
so we can say \(x^2 + 12x + 26\) \(= (x+6)^2 -10 \)
Thats what my calculator said, but i wanted the steps for future reference, Thanks
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