Yea...
If \[x+y=3and3x+5y=13\] then was is \[x-y\] I got \[-1\] as my answer
The goal is to find a value for \(x\) and a value for \(y\).
\[x=1\]\[y=2\]
\[1-2=-1\]
And what steps did you perform to find x and y?
Mental math.
No, you have to show actual steps.
Or rather, post the mental math you did in your head on paper.
I know \[5*2=10\] so I subtracted that and got \[3x=3\] Divide by 3 and you get \[x=1\]
Or rather, electronic format in this case.
No, you have to do it deductively. That process you posted is not "deductive" or done using rules of algebra.
e.e
Did I not get the right answers?
Right answers, incorrect reasoning.
It was mental, it doesn’t have reasoning
Okay put it this way, there are some valid ways to solve this. You can use Elimination Method or Substitution Method. You are only allowed to use one of these methods to solve it.
I hate both of them
They are both essential to know.
Help wizard ~-~
Let x + y = 3 represent equation (1) and 3x + 5y = 13 represent equation (2): Then (1) x + y = 3 (2) 3x + 5y = 13 Elimination Method is as follows: Multiply both sides of equation (1) by 3 to get: 3x + 3y = 9 3x + 5y = 13 Subtract equation (2) from equation (1) to get: -2y = -4 Add 4 to both sides, then 2y to both sides to get: 2y = 4 Divide both sides by 2 to get: y = 2
Ooo, then I plug in y to get x
Correct.
Which would be 1
Substitution Method is as follows: (1) x + y = 3 (2) 3x + 5y = 13 In equation (1) subtract x from both sides to get: y = 3 - x Substitute the expression for y in equation (2) 3x + 5(3 - x) = 13 Then solve for x: 3x + 15 - 5x = 13 3x - 5x = 13 - 15 (3 - 5)x = -2 -2x = -2 2x = 2 x = 1
Plug value for x back into equation (1) to find y.
Neither method is difficult. In some cases Substitution would be simplest method. In other cases, Elimination method will be most useful.
I gotcha.
Moving on :)
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