Solve for x in the equation.
Okay ...
\[\frac{ 3(x-6) }{ 5 }=x\]
x=-9
Show. Your. Work.
Calculator. Did. My. Work.
One moment,
Calculator. Is. Not. Your. Work.
Nope, the calculator is not the appropriate substitution for your work. If you're going to use a calculator, you don't even need to post here.
Your steps are not correct because you removed variable \(x\) from the expressions which is not consistent. \(x\) needs to be there in order for the expressions you create during the solving process to be equivalent expressions. Using equivalent expressions is part of the process of solving algebraic expressions.
\(x\) is missing on the left side of the equation. Notice in the original equation \(x\) occurs on both sides of the equation.
Then I don’t know..
Let's do it this way:
\(\dfrac{3(x - 6)}{5} = x\) Multiply both sides by \(5\). Post your result here using \(\LaTeX\)
\[3(x-6)=5x\]
On the left side of the equation, use the distributive property to expand the expression.
\[3x-18=5x\]
Next, subtract \(3x\) from both sides.
\[-18=2x\]
Divide both sides by \(2\)
X=-9
Now, take the value for \(x\) and substitute it in place of \(x\) in the original equation. Do not do any other step besides what I have already stated and post what you've done here using \(\LaTeX\)
\[\frac{ 3(-9-6) }{ 5 }=-9\]
There you go. That is the correct way to substitute.
And then you would continue to simplify the left side until you get \(-9 = -9\). Of course I prefer to get \(0 = 0\).
So you don’t have negatives?
No, it's just that \(0 = 0\) is the most consistent way of demonstrating both sides equal when substituting the \(x\) you found back to the original equation and simplifying to determine whether both sides agree. For any substitution, you can always end with \(0 = 0\).
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