Help please!! Geometry question
@hardlyhuman, welcome back to QC. Hope you're doing well today. How far did you get in your attempt to solve this one?
I narrowed down an answer based on what I physically saw.
And I'm doing alright, thank you. How are you?
I'm doing good, but I'm a little concerned about your problem solving approach here. Do you really think that physically observing this is more accurate than using the Law of Sines?
No of course not, I'm just gonna tell you straight up; I missed two years of math (7th and 8th) so I'm pretty much lost when it comes to this stuff.
Well, even if that is true, the law of sines is a very easy rule to apply here. The law of sines states that if you have a triangle with sides a, b, and c, and angles A, B, C, such at side a corresponds with Angle A, and side b corresponds with Angle B, and side c corresponds with Angle C then: \(\dfrac{\sin(A)}{a} = \dfrac{\sin(B)}{b} = \dfrac{\sin(C)}{c}\)
In this case we can say side a = 10 which corresponds with Angle A = 31 degrees side b = GH which corresponds with Angle B = 45 degrees
Then we can just use the proportion: \(\dfrac{\sin(A)}{a} = \dfrac{\sin(B)}{b}\) and plug in those values to this formula. We won't need to use any values involving sides c and Angle C here.
If we plug in those given values, we'll end up with: \(\dfrac{\sin(31^{\circ})}{10} = \dfrac{\sin(45^{\circ})}{GH}\)
Now all we have to do is re-arrange this so that we have \(GH = \text{ an equivalent expression to the one above}\)
Then we would simplify that expression using a calculator which would give us the value of side GH
Okay
@hardlyhuman what is the expression equivalent to side \(GH\)?
I don't know, I don't understand it
|dw:1525294364615:dw|
First we label the sides above which reflects what I wrote earlier: In this case we let side a = 10 which corresponds with Angle A = 31 degrees side b = GH which corresponds with Angle B = 45 degrees
|dw:1525294518906:dw| The arrows represent the correspondences between the angles and sides we will use in the Law of Sines formula.
Does this information help you?
yes thank you
So where are you stuck now?
Is it 13.7?
Yes, correct. You surprise me. Can you show the work you did to get that?
I did it on an online sketch board and I closed the window when I was done
Would you mind replicating your steps here. We have a drawing button below the comment box.
I actually gotta go, I have on site testing I need to get to before traffic hits. Thank you for the help though.
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