Expressions
\[27\frac{ 5 }{ 3 }\] \[\sqrt[3]{27^5}\] \[3^5\] \[243\]
And what are the instructions given for these expressions?
“Simplify each expression without any rational exponents.”
Correct
Okay. It should be written as `\(27^{5/3}\)`
Sorry, thanks 🙏
\(27^{5/3}\) = \((3^3)^{5/3} = 3^{\left(3\cdot \dfrac{5}{3}\right)}\)
Sorry for taking so long but this was a bit of a trick one. Not really, but in order to do this the simplest possible way you would have had to apply the rule:
\((a^{b})^{c} = (a^{(bc)})\)
Also there is more than one way to do this. But hang on let me verify something real quick.
\((3^3)^{5/3} = 3^{\left(3\cdot \dfrac{5}{3}\right)}\) And so that last step reduces to just \(3^5\) because the 3's in the exponent cancel.
Which simplifies down to 243 right?
Yes, but now I'm wondering what you did to get from your 2nd step to your 3rd step.
I'm thinking you probably used some illegal shortcut method to reduce it but prove me wrong.
You mean to go from a exponent to a square root?
I want to know the RULE you applied going from step 2 to step 3 in the solution you posted above.
Basically, I would like to see the full steps you applied and the rules you applied.
Without the shortcuts.
I just took the cube root of 27
So probably was illegal..
I would like to see the work you did on it though. Yeah, it probably was illegal if you can't show your work for it.
I showed you the work AND the rules I applied for the work I did.
The only thing I see in your work is a bunch of skipped steps unexplained.
I. Not good like that..
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