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Mathematics 18 Online
EndersWorld:

Expressions

EndersWorld:

\[27\frac{ 5 }{ 3 }\] \[\sqrt[3]{27^5}\] \[3^5\] \[243\]

Hero:

And what are the instructions given for these expressions?

EndersWorld:

“Simplify each expression without any rational exponents.”

EndersWorld:

Correct

Hero:

Okay. It should be written as `\(27^{5/3}\)`

EndersWorld:

Sorry, thanks 🙏

Hero:

\(27^{5/3}\) = \((3^3)^{5/3} = 3^{\left(3\cdot \dfrac{5}{3}\right)}\)

Hero:

Sorry for taking so long but this was a bit of a trick one. Not really, but in order to do this the simplest possible way you would have had to apply the rule:

Hero:

\((a^{b})^{c} = (a^{(bc)})\)

Hero:

Also there is more than one way to do this. But hang on let me verify something real quick.

Hero:

\((3^3)^{5/3} = 3^{\left(3\cdot \dfrac{5}{3}\right)}\) And so that last step reduces to just \(3^5\) because the 3's in the exponent cancel.

EndersWorld:

Which simplifies down to 243 right?

Hero:

Yes, but now I'm wondering what you did to get from your 2nd step to your 3rd step.

Hero:

I'm thinking you probably used some illegal shortcut method to reduce it but prove me wrong.

EndersWorld:

You mean to go from a exponent to a square root?

Hero:

I want to know the RULE you applied going from step 2 to step 3 in the solution you posted above.

Hero:

Basically, I would like to see the full steps you applied and the rules you applied.

Hero:

Without the shortcuts.

EndersWorld:

I just took the cube root of 27

EndersWorld:

So probably was illegal..

Hero:

I would like to see the work you did on it though. Yeah, it probably was illegal if you can't show your work for it.

Hero:

I showed you the work AND the rules I applied for the work I did.

Hero:

The only thing I see in your work is a bunch of skipped steps unexplained.

EndersWorld:

I. Not good like that..

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