Question

HElp

Answer 1

@Vocaloid

Answer 2

2nd one on the list,

sin(a-b) = sin(pi/2 - x) so a is pi/2 and b is x

plug these into sin(a-b) = sin(a)cos(b) - cos(a)sin(b) and simplify using the unit circle values when applicable, your result should be cos(x)

Answer 3

sin(pi/2 - x) = sin(a)cos(b) - cos(a)sin(b)

Answer 4

a is pi/2 and b is x

with that being said, what does sin(a)cos(b) - cos(a)sin(b) equal?

Answer 5

sin(pi/2)cos(x) - cos(pi/2)sin(x)

Answer 6

good, now plug in the values for sin(pi/2) and cos(pi/2), what do you get?

Answer 7

look at the UC, what are the values of sin(pi/2) and cos(pi/2)?

Answer 8

0,1

Answer 9

good, sin(pi/2) = 1 and cos(pi/2) = 0
now plug these into the equation

sin(pi/2)cos(x) - cos(pi/2)sin(x)

and simplify your result

Answer 10

sin(pi/2) = 1 and cos(pi/2) = 0
sin(pi/2)cos(x) - cos(pi/2)sin(x)
1(0)-0-1=

Answer 11

If I'm doing this right :/

Answer 12

keep in mind sin(pi/2) = 1 and cos(pi/2) = 0; we don't know what cos(x) and sin(x) are so you must leave them alone

Answer 13

sin(pi/2) = 1 and cos(pi/2) = 0
sin(pi/2)cos(x) - cos(pi/2)sin(x)
1 (cos x) - 0 (sin x)

Answer 14

awesome, and that simplifies to cos(x) thus fulfilling the original proof

Answer 15

so 1 (cos x )(sin x)

Answer 16

OH okay